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AVprozaik [17]
3 years ago
10

What are the basic functions and parts of an LED bulb?? Please Help!!

Chemistry
1 answer:
IgorLugansk [536]3 years ago
5 0

Answer:

Lens

Heat Sink

Housing

Base

Circuit Board/Driver

LED Chips

Explanation:

Does this help you?

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Consider a hydrogen atom in the ground state. What is the energy of its electron?
mr Goodwill [35]
The energy of an electron in a hydrogen atom is:
<span>E= (-2.179 x 10 ^-18 J)(1/n^2)

</span>where n is the principle energy level of the electron.
<span>
E= (-2.179 x 10 ^-18 J)(1/4)
</span><span>E= -2.179 x 10 ^-18 J
</span>E = -5.4 <span>x 10 ^-19 J</span>
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The elements most likely to form more than one type of ion are thetransition metals
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Good day please help me thank you
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Calculate the mass in grams of each sample.
OlgaM077 [116]

Answer: The answer is A. - 4.88x10^20 H2O2 molecules

Explanation: I hope this helps!

4 0
3 years ago
The activation energy of a certain uncatalyzed reaction is 64 kJ/mol. In the presence of a catalyst, the Ea is 55 kJ/mol. How ma
Ksivusya [100]

Answer:

About 5 times faster.

Explanation:

Hello,

In this case, since the Arrhenius equation is considered for both the catalyzed reaction (1) and the uncatalized reaction (2), one determines the relationship between them as follows:

\frac{k_1}{k_2}=\frac{Aexp(-\frac{Ea_1}{RT} )}{Aexp(-\frac{Ea_2}{RT})}  \\\frac{k_1}{k_2}=\frac{exp(-\frac{Ea_1}{RT} )}{exp(-\frac{Ea_2}{RT})}

By replacing the corresponding values we obtain:

\frac{k_1}{k_2}=\frac{exp(-\frac{55000J/mol}{8.314J/molK*673.15K} )}{exp(-\frac{64000J/mol}{8.314J/molK*673.15K} )} =4.8

Such result means that the catalyzed reaction is about five times faster than the uncatalyzed reaction.

Best regards.

4 0
3 years ago
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