Answer:
The change in the internal energy of the system -878 J
Explanation:
Given;
energy lost by the system due to heat, Q = -1189 J (negative because energy was lost by the system)
Work done on the system, W = -311 J (negative because work was done on the system)
change in internal energy of the system, Δ U = ?
First law of thermodynamics states that the change in internal energy of a system (ΔU) equals the net heat transfer into the system (Q) minus the net work done by the system (W).
ΔU = Q - W
ΔU = -1189 - (-311)
ΔU = -1189 + 311
ΔU = -878 J
Therefore, the change in the internal energy of the system -878 J
Answer:
The answer is
<h2>112.912 kPa</h2>
Explanation:
The new pressure can be found by using the formula for Boyle's law which is

Since we are finding the new pressure

404.6 kPa = 404600 Pa
From the question we have

We have the final answer as
<h3>112.912 kPa</h3>
Hope this helps you