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qwelly [4]
3 years ago
5

In an experiment different wavelengths of light, all able to eject photoelectrons, shine on a freshly prepared (oxide-free) zinc

surface. Which statement is true
Physics
1 answer:
topjm [15]3 years ago
6 0

Answer:

the energy of the photons is greater than the work function of the zinc oxide.

                     h f> = Ф

Explanation:

In this experiment on the photoelectric effect, it is explained by the Einstein relation that considers the light beam formed by discrete energy packages.

                    K_max = h f - Ф

in the exercise phase, they indicate that different wavelengths can inject electrons, so the energy of the photons is greater than the work function of the zinc oxide.

                     h f > = Ф

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An electromagnetic wave of wavelength 435 nm is traveling in vacuum in the —z direction. The electric field has an amplitude of
Aloiza [94]

Answer:

a) 6.9*10^14 Hz

b) 9*10^-12 T

Explanation:

From the question, we know that

435 nm is given as the wavelength of the wave, at the same time, we also know that the amplitude of the electric field, E(max) has been given to be 2.7*10^-3 V/m

a)

To find the frequency of the wave, we would be applying this formula

c = fλ, where c = speed of light

f = c/λ

f = 3*10^8 / 435*10^-9

f = 6.90*10^14 Hz

b) again, to find the amplitude of the magnetic field, we would use this relation

E(max) = B(max) * c, magnetic field amplitude, B(max) =

B(max) = E(max)/c

B(max) = 2.7*10^-3 / 3*10^8

B(max) = 9*10^-12 T

c) and lastly,

1T = 1 (V.s/m^2)

6 0
3 years ago
An object is initially moving at an unknown velocity. It accelerates at a rate of 1.5m/s2 to a new velocity of 60 m/s in 25 s. W
Alexandra [31]
<h3>Answer:  22.5 m/s</h3>

=====================================================

Work Shown:

acceleration = ( finalVelocity - initialVelocity )/(change in time)

1.5 = (60 - x)/(25)

1.5*25 = 60-x

37.5 = 60-x

x = 60-37.5

x = 22.5

The initial velocity is 22.5 m/s

6 0
3 years ago
Chet believes that electric fields can impact objects only when the objects are in direct contact. Tonya disagrees with Chet. Wh
Murljashka [212]

B because it is the only evidence that displays an effect from the field without contact

3 0
3 years ago
Please help fast, 30 Points, Brainliest Answer
maksim [4K]

A.) Cubic meters is your answer

Cubic meters are used to measure the volume of solids.

hope this helps

4 0
3 years ago
Air enters an adiabatic compressor at 104 kPa and 292 K and exits at a temperature of 565 K. Determine the power (kW) for the co
ladessa [460]

Answer:

\dot W_{in} = 49.386\,kW

Explanation:

An adiabatic compressor is modelled as follows by using the First Law of Thermodynamics:

\dot W_{in} + \dot m \cdot c_{p}\cdot (T_{1}-T_{2}) = 0

The power consumed by the compressor can be calculated by the following expression:

\dot W_{in} = \dot m \cdot c_{v}\cdot (T_{2}-T_{1})

Let consider that air behaves ideally. The density of air at inlet is:

P\cdot V = n\cdot R_{u}\cdot T

P\cdot V = \frac{m}{M}\cdot R_{u}\cdot T

\rho = \frac{P\cdot M}{R_{u}\cdot T}

\rho = \frac{(104\,kPa)\cdot (28.02\,\frac{kg}{kmol})}{(8.315\,\frac{kPa\cdot m^{3}}{kmol\cdot K} )\cdot (292\,K)}

\rho = 1.2\,\frac{kg}{m^{3}}

The mass flow through compressor is:

\dot m = \rho \cdot \dot V

\dot m = (1.2\,\frac{kg}{m^{3}})\cdot (0.15\,\frac{m^{3}}{s} )

\dot m = 0.18\,\frac{kg}{s}

The work input is:

\dot W_{in} = (0.18\,\frac{kg}{s} )\cdot (1.005\,\frac{kJ}{kg\cdot K})\cdot (565\,K-292\,K)

\dot W_{in} = 49.386\,kW

5 0
3 years ago
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