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Nitella [24]
4 years ago
5

A 20-kg wagon accelerates on a horizontal surface at 0.50 m⁄s2 when pulled by a rope exerting a 120-N force on the wagon at an a

ngle of 25° above the horizontal. Determine the magnitude of the effective friction force exerted on the wagon and the effective coefficient of friction associated with this force.

Physics
1 answer:
inn [45]4 years ago
5 0

Answer:

Explanation:

given,

mass of wagon = 20 Kg

horizontal acceleration = 0.5 m/s²

force of pull = 120 N

angle with horizontal = 25°

Applying newtons second law

F cos θ - f = m a

f = F cos θ- ma

f = 120 cos 25° - 20 x 0.5

f = 99 N

we know,

f = μ N

μ =\dfrac{f}{N}

μ =\dfrac{99}{mg - Fsin \theta}

μ =\dfrac{99}{20\times 9.8 - 120 sin 25^0}

μ = 0.68

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At a distance of 1.33 m 250-N load be hung on the pole, such that the father will carry twice the load of his son.

<h3>What is torque?</h3>

Torque is the force's twisting action about the axis of rotation. Torque is the term used to describe the instant of force. It is the rotational equivalent of force.

Torque about the left end ;

\rm F_s \times 5 m -W_l (x)-W_P(2.5)=0\\\\ 5F_S-250x-W_P(2.5)=0\\\\F_m+F_s=W_L+W_P\\\\\ F_m+F_s=350 \ N\\\\

From  the observation,

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After rearranging equation, we get;

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Substitute the value of the obtained force we get;

x=1.33 m


Hence, at a distance of 1.33 m ,250-N load be hung on the pole, such that the father will carry twice the load of his son.

To learn more about the torque refer to the link;

brainly.com/question/6855614

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This question actually seeks to test our knowledge of the law of momentum. The law of conservation of momentum states that the momentum of a closed system is conserved.

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