Why do stretching exercises increase flexibility more than cardio exercises?

1 answer:

5 0

Stretching exercises increase flexibility more than cardio exercises because stretching exercises stretches your muscles in around your body while cardio exercises only work out the muscles of your cardiovascular system. <span>It will help you in endurance but not so much in flexibility.</span>

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Each of the different colors that make up white light has a different ___________________.

Verdich [7]

Answer:

Wavelength?

Explanation:

7 0

3 years ago

A cube of wood having an edge dimension of 20.0cm and a density of 650 kg /m³ floats on water. (a) What is the distance from the

Zarrin [17]

The distance from the horizontal top surface of the cube to the water level is "6.282 cm".

<h3>What is Archimedes' principle?</h3>

According to Archimedes' principle, the weight of the fluid that the body displaces is equal to the upward buoyant force that is applied to a body submerged in a fluid, whether fully or partially. The Archimedes' principle is a fundamental physical law in fluid mechanics. It was created by Syracuse's Archimedes.

According to Archimedes' principle, a body submerged in a fluid experiences an upward force proportional to the weight of the fluid that has been displaced. One of the prerequisites for equilibrium is this. We believe that the buoyancy force, also known as the centre of buoyancy, is situated in the middle of the submerged hull.

From Archimedes' principle, we get

$\rightarrow L^3 \rho_{\text {Wood }} &=L^2 d \rho_{\text {Water }} \\$

$d &=L \frac{\rho_{\text {Waat }}}{\rho_{\text {Water }}} \\$

$&=18 \times \frac{651}{1000} \\$

=11.72cm

So,

The distance from horizontal top to the water level will be:

=18-11.72

=6.282cm

To learn more about Archimedes' principle refer to:

brainly.com/question/1155674

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4 0

1 year ago

An object of mass m is traveling in a circle with centripetal force f c. If the velocity of the object is v, what is the radius

Gnom [1K]

Answer:

r = mv^2/ Fc

Explanation:

Got it right

7 0

3 years ago

A 7kg block slides down a 30 degree slope at a constant velocity of 2 m/s. How big is the force of friction acting on the block?

lisabon 2012 [21]

The force of friction is <u>34.3 N.</u>

A block of mass m slides down a plane inclined at an angle θ to the horizontal with a constant velocity. According to Newton's first law of motion, every body continues in its state of rest or a state of uniform motion in a straight line, unless acted upon, by an external unbalanced force. This means that when balanced forces act on a body, the body moves with a constant velocity.

The free body diagram of the sliding block is shown in the attached diagram. Resolve the weight mg of the block into two components mg sinθ along the direction of the plane and mg cosθ perpendicular to the plane . The force of friction F acts upwards along the plane and the normal reaction acts perpendicular to the plane.

Since the block moves down with a constant velocity, the downward force mg sinθ must be equal to the upward frictional force.

$F = mg sin\theta$