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n200080 [17]
3 years ago
11

Why do stretching exercises increase flexibility more than cardio exercises?

Physics
1 answer:
hichkok12 [17]3 years ago
5 0
Stretching exercises increase flexibility more than cardio exercises because stretching exercises stretches your muscles in around your body while cardio exercises only work out the muscles of your cardiovascular system. <span>It will help you in endurance but not so much in flexibility.</span>
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The cricket ball has a mass of 0.16kg and it hits the bat with a speed of 25 m/s. After being in contact with the bat for 0.0013
zavuch27 [327]

change in velocity is 3m/s,the force exterted by bat on ball is 4.8N and the acceleration is 30m/s².

<h3>Give  some difference between velocity and speed.</h3>

1) Speed is scalar quantity but velocity is vector quantity.

2) Speed is distance followed by an individual with respect to  time and velocity is displacement with respect to time .

1) final velocity- intial velocity

 25-22= 3m/s

2) The force is

F= ma

 . 0.16×30= 4.8N

to learn more about speed and velocity click brainly.com/question/19425181

#SPJ9

7 0
1 year ago
What was the orginal purpose of the constitutional convention and what conclusion did they quickly came to?
klio [65]
The original purpose was to reform the articles of the confederation and fix them but they decided to completely scrap it and write the constitution we have in place today
4 0
3 years ago
How many types Of Ornital does the atomic orbital have ?​
bixtya [17]

Answer:

There are four types of orbitals that you should be familiar with s, p, d and f (sharp, principle, diffuse and fundamental). Within each shell of an atom there are some combinations of orbitals

3 0
2 years ago
Read 2 more answers
To practice Problem-Solving Strategy 27.1: Magnetic Forces. A particle with mass 1.81×10−3 kgkg and a charge of 1.22×10−8 CC has
Roman55 [17]

Answer:

The magnitude of the acceleration  is a = 0.33 m/s^2

The direction is - \r k i.e the negative direction of the z-axis

Explanation:

 From  the question we are that

       The mass of the particle m = 1.8*10^{-3} kg

         The charge on the particle is q = 1.22*10^{-8}C

         The velocity is \= v = (3.0*10^4 m/s ) j

        The the magnetic field is  \= B = (1.63T)\r i + (0.980T) \r j

The charge experienced  a force which is mathematically represented as

         

                    F = q (\= v * \= B)

    Substituting value

         F = 1.22*10^{-8} (( 3*10^4 ) \r j \ \ X \ \  ( 1.63 \r i  + 0.980 \r j )T)

            = 1.22 *10^{-8} ((3*10^4 * 1.63)(\r j \ \  X \ \  \r i) + (3*10^4 * 0.980) (\r j \ \ X \ \  \r  j))

            = (-5.966*10^4 N) \r k

Note :

           i \ \ X \ \ j = k \\\\j \ \  X  \ \ k = i\\\\k  \ \ X \ \ i = j\\\\j \ \ X \ \ i = -k \\\\k \ \  X  \ \ j = -i\\\\i  \ \ X \ \ k = - j\\

Now force is also mathematically represented as

        F = ma

Making a the subject

      a = \frac{F}{m}

   Substituting values

     a =\frac{(-5.966*10^4) \r k}{1.81*10^{-3}}

        = (-0.33m/s^2)\r k

        = 0.33m/s^2 * (- \r k)

6 0
3 years ago
An air balloon is moving upward at a constant speed of 3 m/s. Suddenly a passenger realizes that she left her camera on the grou
frosja888 [35]

Answer:t=0.3253 s

Explanation:

Given

speed of balloon is u=3\ m/s

speed of camera u_1=20\ m/s

Initial separation between camera and balloon is d_o=5\ m

Suppose after t sec of  throw camera reach balloon then,

distance travel by balloon is

s=ut

s=3\times t

and distance travel by camera to reach balloon is

s_1=ut+\frac{1}{2}at^2

s_1=20\times t-\frac{1}{2}gt^2

Now

\Rightarrow s_1=5+s

\Rightarrow 20\times t-\frac{1}{2}gt^2 =5+3t

\Rightarrow 5t^2-17t+5=0

\Rightarrow t=\dfrac{17\pm \sqrt{17^2-4(5)(5)}}{2\times 5}

\Rightarrow t=\dfrac{17\pm 13.747}{10}

\Rightarrow t=0.3253\ s\ \text{and}\ t=3.07\ s

There are two times when camera reaches the same level as balloon and the smaller time is associated with with the first one .

(b)When passenger catches the camera time is  t=0.3253\ s

velocity is given by

v=u+at

v=20-10\times 0.3253

v=16.747\ m/s

and position of camera is same as of balloon so

Position is =5+3\times 0.3253

=5.975\approx 6\ m

8 0
3 years ago
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