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Fantom [35]
4 years ago
15

Susan is making an electromagnet in her science class today. First, she takes a nail and winds coils of copper wire around it th

en, she
connects the ends of the wire to a battery. She uses the electromagnet to pick up paper clips, but the paper clips drop when she
disconnects the wires from the battery, Which kind of energy does Susan change into magnetic energy in this project
chemical
electrical
heat
light
Physics
2 answers:
matrenka [14]4 years ago
5 0

Answer:

Electrical

Explanation:

She uses a battery, which is electrical.

It doesn't operate using chemicals, heat, or light

Pie4 years ago
4 0

Answer:

it's chemical and electrical because she uses her circuit in which the both forms take place...........so according to me the most probably the answer is electrical.....

Explanation:

because she uses her circuit in which the both forms take place...........so according to me the most probably the answer is electrical.....

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Sirius A has a luminosity of 26 LSun and a surface temperature of about 9400 K.What is its radius?
wlad13 [49]

Answer

Given,

Sirius A surface temperature,T = 9400 K

Sirius A luminosity,L = 26 L₀

L₀ is the luminosity of sun.

Radius of sun =  695700000 m

Temperature on sun surface = 5780 K

Luminous intensity is given by:-

L=4 \pi R^{2} \sigma T^{4}

Now

\frac{L}{L_{0}}=\frac{4 \pi R^{2} \sigma T^{4}}{4 \pi R_{0}^{2} \sigma T_{0}^{4}}=26

\Rightarrow \frac{R^{2} T^{4}}{R_{0}^{2} T_{0}^{4}}=26

\Rightarrow R^{2}=26 \times \frac{R^{2} T_{0}^{4}}{T^{4}}=26 \times \frac{695700000^{2} \times 5780^{4}}{9400^{4}}

R=1341246640\ m=1.34 \times 10^{9}

7 0
3 years ago
Which layer of the atmosphere has the lowest density?
stich3 [128]
Hello,

The exosphere is the lowest<span> in density of the </span>layers of the atmosphere.

The higher up you get into the atmosphere, the lower the density becomes. Thus, the troposphere has the highest density of the five layers. 

Faith xoxo
6 0
3 years ago
The angle θ is slowly increased. Write an expression for the angle at which the block begins to move in terms of μs.
Reika [66]

Answer:

tan \theta = \mu_s

Explanation:

An object is at rest along a slope if the net force acting on it is zero. The equation of the forces along the direction parallel to the slope is:

mg sin \theta - \mu_s R =0 (1)

where

mg sin \theta is the component of the weight parallel to the slope, with m being the mass of the object, g the acceleration of gravity, \theta the angle of the slope

\mu_s R is the frictional force, with \mu_s being the coefficient of friction and R the normal reaction of the incline

The equation of the forces along the direction perpendicular to the slope is

R-mg cos \theta = 0

where

R is the normal reaction

mg cos \theta is the component of the weight perpendicular to the slope

Solving for R,

R=mg cos \theta

And substituting into (1)

mg sin \theta - \mu_s mg cos \theta = 0

Re-arranging the equation,

sin \theta = \mu_s cos \theta\\\rightarrow tan \theta = \mu_s

This the condition at which the equilibrium holds: when the tangent of the angle becomes larger than the value of \mu_s, the force of friction is no longer able to balance the component of the weight parallel to the slope, and so the object starts sliding down.

4 0
4 years ago
An object has an acceleration of 6.0 m/s/s. If the net force was doubled and the mass was one-third the original value, then the
alexandr402 [8]

Hahahahaha. Okay.

So basically , force is equal to mass into acceleration.

F=ma

so when F=ma , we get acceleration=6m/s/s

Force is doubled.

Mass is 1/3 times original.

2F=1/3ma

Now , we rearrange , and we get 6F=ma

So , now for 6 times the original force , we get 6 times the initial acceleration.

So new acceleration = 6*6= 36m/s/s

5 0
4 years ago
Please help! Giving 20 points!!
MrMuchimi

Answer:

Explanation:

Remark

This is a momentum question. Both cars are sitting still (v1 and v2 are both 0) to start with). When the spring is sprung), they both move but in opposite directions.

Let us say that v4 is minus.

Equation

0 = m3*v3 - m4* v4

Givens

m3 = 1750 kg

m4 = 1000 kg

v3 = 4 m/s

Solution

m3*4m/s - m4*x = 0

1750 * 4 - 1000*x = 0

1750 * 4 = 1000x

7000 = 1000 x

7000/1000 = x

x = 7 m/s

7 0
3 years ago
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