Answer:
- the Thevenin equivalent circuit for the battery is uploaded below
- the battery delivered 117 watts of power to the starter motor
Explanation:
Given the data in the equation
diagram of the Thevenin equivalent circuit for the battery is uploaded below.
Current I = 10 A
Voltage 1 = 12 V
voltage 2 = 11.7 v
R = (V1 - V2) / I
R = (12-11.7)/10
R = 0.3 / 10
R = 0.03Ω
Thevenin equivalent circuit
= V2 / I = 11.7 / 10
= 1.17Ω
so, power delivered to the starter motor will be;
p = (V2)² /
P = ( 11.7 V )² / 1.17Ω
p = 136.89 / 1.17
p = 117 watts
Therefore, the battery delivered 117 watts of power to the starter motor
I would say the answer to your question is A Ferris wheel turning at a constant speed. The reasoning behind this answer is the fact that traveling in a constant direction at a constant speed is not accelerating. The Ferris wheel is the only option that fits this description. The last option would be incorrect due to independent causes such as speed limit changes as well as turns and stops on the highway.
Given: Plank's constant h = 6.626 x 10⁻³⁴ J.s
Speed of light c = 2.998 x 10⁸ m/s
Wavelength λ = 500 nm convert to meter = 5 x 10⁻⁷ m
Required: Energy E =?
Formula: E = hc/λ
E = (6.626 X 10⁻³⁴ J.s)(2.998 X 10⁸ m/s)/5 x 10⁻⁷ m
E = 3.97 X 10⁻¹⁹ J or in termS of electron volt
E = 2.48 eV
The horizontal motion of a launched projectile affects its vertical motion is false
Answer: False
<u>Explanation:
</u>
As the trajectory falls on a plane, all the components like displacement, velocity can be classified in two components termed as horizontal and vertical component.
In a projectile motion, the horizontal components of displacement and velocity remains constant and there is change only in the vertical component of displacement and velocity.
Both components are not dependent to each other. So, the horizontal motions of a launched projectile does not affect its vertical motion.
