1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Setler79 [48]
2 years ago
14

Which type of precipitation is most likely to form during a thunderstorm A sleet

Chemistry
2 answers:
Scilla [17]2 years ago
8 0

Answer:

Explanation:

"B" is the correct answer.

Hope it helps you!

Muska~

Arte-miy333 [17]2 years ago
4 0

Answer:

<h2>hail</h2>

Explanation:

<h3><u>Large updrafts of air can throw rain droplets high up into the tops of the cloud.</u></h3>
You might be interested in
How many moles are present in
olasank [31]

Answer: (a) There are 0.428 moles present in 12 g of N_{2} molecule.

(b) There are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

Explanation:

(a). The mass of nitrogen molecule is given as 12 g.

As the molar mass of N_{2} is 28 g/mol so its number of moles are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{12 g}{28 g/mol}\\= 0.428 mol

So, there are 0.428 moles present in 12 g of N_{2} molecule.

(b). According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

Therefore, moles present in 12.044 \times 10^{23} particles are calculated as follows.

Moles = \frac{12.044 \times 10^{23}}{6.022 \times 10^{23}}\\= 2 mol

So, there are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

4 0
3 years ago
How many grams of salt are in 1 kilogram of seawater with average salinity? quizzlet?
Degger [83]
<span>35 grams The average salinity of seawater is 35 parts per thousand, so multiply the mass of seawater provided by 0.035 and you'll get the amount of salt (mostly sodium chloride) dissolved in it. So 1000 g * 0.035 = 35 g Therefore in 1 kilogram of seawater with average salinity, there is 35 grams of salt.</span>
5 0
3 years ago
Limitation for osmosis experiment
taurus [48]
What was the question here?
5 0
2 years ago
Earth
Juliette [100K]
Full moon I’m pretty sure... good luck!
3 0
3 years ago
A 25.00 ml sample of h3po4 solution is neutralized by exactly 54.93 ml of 0.04345 m ca(oh)2. what is the molarity of the h3po4 s
son4ous [18]
The neutralization equation is:
3 Ca(OH)₂ + 2 H₃PO₄ → Ca₃(PO₄)₂ + 6 H₂O

From this equation we can see that 3 moles of Ca(OH)₂ react with 2 moles of H₃PO₄

Numbers of mmol of Ca(OH)₂ = M x V = 0.04345 x 54.93 = 2.387 mmol

Number of mmol of H₃PO₄ = 2.387 x (2/3) = 1.591 mmol

Molarity of solution = n (mmol) / V(ml) = 1.591 / 25 = 0.0636 M
8 0
3 years ago
Read 2 more answers
Other questions:
  • A study of the decomposition reaction 3RS2  3R + 6S yields the following initial rate dat
    6·1 answer
  • Pb(BrO3)2 is a ionic compound,covalent compound, or Acid
    12·1 answer
  • Blank of water is a physical change because boiling the water is blank from a liquid to a gas
    5·2 answers
  • A buffer of pH 9.24 is to be prepared from a weak acid and its salt. The best acid from which to prepare the buffer is
    12·1 answer
  • Friction depends on the types of surfaces involved and how hard the surfaces push together.
    11·2 answers
  • -<br> What is the mass of the following particles:<br> o Protons<br> o Neutrons<br> o Electrons
    8·1 answer
  • Which of the following destroys the marine ecosystem?
    15·2 answers
  • TEST Ch 10 Moles- Part B Math
    9·1 answer
  • How many moles of H2O form when 4.5 moles O2 reacts?
    14·1 answer
  • How can we identify that the absorption of heat has occurred?​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!