The relative velocity of the athlete relative to the ground is 5.2 m/s
The given parameters;
constant velocity of the athlete, V = 5.2 m/s
let the velocity of the ground = Vg = 0
The relative velocity concept helps us to determine the velocity of a moving object relative to a stationary observer.
The athlete is the moving object in this question while the ground is stationary.
The relative velocity of the athlete relative to the ground is calculated as follows;
Thus, the relative velocity of the athlete relative to the ground is 5.2 m/s
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Answer:
you will feel warm
Explanation:
beacause your body will get the warm from warm water tap..
Come se in so mi tiempo si
Answer:
0° C
Explanation:
Given that
Mass of ice, m = 50g
Mass of water, m(w) = 50g
Temperature of ice, T(i) = 0° C
Temperature of water, T(w) = 80° C
Also, it is known that
Specific heat of water, c = 1 cal/g/°C
Latent heat of ice, L(w) = 89 cal/g
Let us assume T to be the final temperature of mixture.
This makes the energy balance equation:
Heat gained by ice to change itself into water + heat gained by melted ice(water) to raise its temperature at T° C = heat lost by water to reach at T° C
m(i).L(i) + m(i).c(w)[T - 0] = m(w).c(w)[80 - T], on substituting, we have
50 * 80 + 50 * 1(T - 0) = 50 * 1(80 - T)
4000 + 50T = 4000 - 50T
0 = 100 T
T = 0° C
Thus, the final temperature is 0° C
Answer:
Car 1 and Car 2 have the same momentum!
Explanation:
Using the formula of momentum (P=m*v), we get for each car:
Car 1: 5kg*2.2m/s = 11kg*m/s
Car 2: 5.5kg*2m/s = 11kg*m/s
Car 3: 6kg*1.35m/s = 8.1kg*m/s
Car 4: 6.5kg*1.9m/s = 12.35kg*m/s
Car 5: 7kg*1.25m/s = 8.75kg*m/s
