A motorboat accelerates uniformly from a velocity of 6.5m/s
to the west to a velocity of 1.5m/s to the west. if its accelerate was 2.7m/s2
to the east ,
how far did it travel during the accelration? Give your
answer in units of kilometers per hour/sec. To find the acceleration of the car
we have to
<span>
1. First determine
the suitable formula for this word problem.
Which is a. A=vf-vi/t</span>
which will be
Given are: Vi= 6.5 m/s Vf= 1.5 m/s a= 2.7 m/sec2 t=1.85s
Solution:
<span>
x = v0t + ½at2</span>
<span>x = <span>16.645375 m </span></span>
Assuming the same deformation and elastic modulus, we can use the relationship:
(P/D)1 = (P/D)2
Where P is the load, Dis the diameter of the wire, 1 is the first wire, and 2 is the second wire. Using the given values and solving for the diameter of the second wire:
D = (24 / 0.24) (1)
D = 100 mm
The correct option for the above statement is:
It moves up and down or back and forth, but it does not move forward with the wave.
Explanation:
Waves may be separated into crosswise and longitudinal waves in an exceedingly crosswise wave, the motion of the particles of the medium is at right angles (i.e., transverse) to the direction the wave moves. The particles on the surface of the traveling in circular ways as a wave moves across the surface.
Answer:
180 [J].
Explanation:
1) the required work [W] can be calculated as difference of the energy: W=E₂-E₁, where E₁=mgh₁ - the energy before lifting, E₂=mgh₂ - the energy after lifting;
2) W=mgh₂-mgh₁, where m - mass; g=10 [N/kg], h - height;
3) then the required work [W]:
W=mg*(h₂-h₁)=30*6=180 [J].
