i wanna learn a little bit of physics so if anyone could teach me a thing or two it would be much appreciated

Physics

2 answers:

AVprozaik [17]3 years ago

8 0

Things I would work on for starting are these Basic principles of physics 

1. Newton's laws of motion. 

2. Mass, force, and weight (Mass versus weight) 

3. Momentum and conservation of energy. 

4. Gravity, theories of gravity. 

5. Energy, work, and their relationship. 

6. Motion, position, and energy.

Apologies if this wasn't what you were searching for. (；′⌒`)

___________________________________________________________

私が始めるために取り組むことは、これらの物理学の基本原理です。

1.ニュートンの運動の法則。

2.質量、力、および重量（質量対重量）

3.勢いとエネルギー保存。

4.重力、重力の理論。

5.エネルギー、仕事、およびそれらの関係。

6.動き、位置、およびエネルギー。

これがあなたが探していたものではなかった場合はお詫び申し上げます。

pentagon [3]3 years ago

4 0

Answer:

... message me. what do u want to know

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What is the magnitude of the magnetic field at a point midway between them if the top one carries a current of 19.5 A and the bo

Phantasy [73]

Answer:

The magnetic field will be $\large{\dfrac{1.4 \times 10^{-4}}{d}} T$ , '2d' being the distance the wires.

Explanation:

From Biot-Savart's law, the magnetic field ( $\large{\overrightarrow{B}}$ ) at a distance ' $r$ ' due to a current carrying conductor carrying current ' $I$ ' is given by

$\large{\overrightarrow{B} = \dfrac{\mu_{0}I}{4 \pi}} \int \dfrac{\overrightarrow{dl} \times \hat{r}}{r^{2}}}$

where ' $\overrightarrow{dl}$ ' is an elemental length along the direction of the current flow through the conductor.

Using this law, the magnetic field due to straight current carrying conductor having current ' $I$ ', at a distance ' $d$ ' is given by

$\large{\overrightarrow{B}} = \dfrac{\mu_{0}I}{2 \pi d}$

According to the figure if ' $I_{t}$ ' be the current carried by the top wire, ' $I_{b}$ ' be the current carried by the bottom wire and ' $2d$ ' be the distance between them, then the direction of the magnetic field at 'P', which is midway between them, will be perpendicular towards the plane of the screen, shown by the $\bigotimes$ symbol and that due to the bottom wire at 'P' will be perpendicular away from the plane of the screen, shown by $\bigodot$ symbol.