i wanna learn a little bit of physics so if anyone could teach me a thing or two it would be much appreciated
2 answers:
<em>Things I would work on for starting are these Basic principles of physics </em>
<em>1. Newton's laws of motion. </em>
<em>2. Mass, force, and weight (Mass versus weight) </em>
<em>3. Momentum and conservation of energy. </em>
<em>4. Gravity, theories of gravity. </em>
<em>5. Energy, work, and their relationship. </em>
<em>6. Motion, position, and energy.</em>
<em>Apologies if this wasn't what you were searching for. (；′⌒`)</em>
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私が始めるために取り組むことは、これらの物理学の基本原理です。
1.ニュートンの運動の法則。
2.質量、力、および重量（質量対重量）
3.勢いとエネルギー保存。
4.重力、重力の理論。
5.エネルギー、仕事、およびそれらの関係。
6.動き、位置、およびエネルギー。
これがあなたが探していたものではなかった場合はお詫び申し上げます。
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Answer:
a) see attached, a = g sin θ
b)
c) v = √(2gL (1-cos θ))
Explanation:
In the attached we can see the forces on the sphere, which are the attention of the bar that is perpendicular to the movement and the weight of the sphere that is vertical at all times. To solve this problem, a reference system is created with one axis parallel to the bar and the other perpendicular to the rod, the weight of decomposing in this reference system and the linear acceleration is given by
Wₓ = m a
W sin θ = m a
a = g sin θ
b) The diagram is the same, the only thing that changes is the angle that is less
θ' = 9/2 θ
c) At this point the weight and the force of the bar are in the same line of action, so that at linear acceleration it is zero, even when the pendulum has velocity v, so it follows its path.
The easiest way to find linear speed is to use conservation of energy
Highest point
Em₀ = mg h = mg L (1-cos tea)
Lowest point
Emf = K = ½ m v²
Em₀ = Emf
g L (1-cos θ) = v² / 2
v = √(2gL (1-cos θ))
