Then the maximum height of the catapult will be 69.78 meters.
<h3>What is kinematics?</h3>
The study of motion without considering the mass and the cause of the motion. The equation of motion is given below.
v = u + at
s = ut + (1/2)at²
v² = u² + 2as
A catapult can project a projectile at a speed as high as 37.0 m/s. (a) if air resistance can be ignored.
a = - 9.81 m/s²
u = 37 m/s
v = 0
s = h
Then the maximum height of the catapult will be given by the third equation.
v² = u² + 2as
0² = 37² - 2 × 9.81 × h
h = 37² / (2 × 9.81)
h = 69.78 meters
Then the maximum height of the catapult will be 69.78 meters.
More about the kinematics link is given below.
brainly.com/question/7590442
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Answer:
47.48 m
Explanation:
The horizontal range of an object can be estimated using the equation below:


For the maximum horizontal range to occur, the angle
is 45°. Then, the horizontal range will be:
= 
In addition, the velocity (v) can be estimated using the equation below:
v = gt/2
Therefore, the maximum horizontal range is:
= (9.81*4.4/2)^2 / 9.81 = 47.48 m
Answer:
Time taken to reach your destination will be 10hours
Explanation:
Recall the formula for Speed;
speed=Total distance/Total time taken
Speed=2km/h
Total distance=20km
Time taken=x
let x be the unknown time taken
Input each values into the formula;
2=20/x
Making x subject of the equation
x=20/2
x=10
Total time taken =10hours.
Look gurrlll or boyyy u need to do ur own work
Answer:
m = 1
Explanation:
K.E = 8J
v = 4m/s
m = ?
Now,
K.E = 1÷2mv^2
8 = 1÷2 × m × (4)^2
8 = 1÷2 × m × 16
8 = m × 8
m × 8 = 8
m = 8 ÷ 8 = 1
m = 1
<h3>
<em><u>VERIFICATION</u></em><em><u>:</u></em></h3>
K.E. = 1÷2mv^2
K.E = 1÷2 × 1 × 4^2
K.E. = 8J
<u>-TheUnknownScientist</u>