The magnitude of the change in momentum of the block between zero and 4. 0 seconds is
dp=1.6m/s
<h3>What is the magnitude of the change in momentum of the block between zero and 4. 0 seconds?</h3>
Generally, the equation for the kinematics equation is mathematically given as
x=x+ut+0.5at^2
Therefore
1.6=0+0+0.5*a*1^2
a=0.2m/s^2
In conclusion, change in momentum
dP=mv-mu
2.0*0.8-0
dp=1.6m/s
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Explanation:
Answer: 2 m/s^2
Explain
£F=ma
net force = mass x acceleration
4N is a force acting on it
4N=(2kg) a
2kg is the mass
you divide the 2 over
and A= 2 m/s^2
