Answer:
VR = 
Explanation:
A machine is a device that can be used to overcome a load by the application of an effort through a pivot. Examples are: pulleys, wedge, screw jack, wheel and axle etc.
The wheel and axle is a simple device that can be used to lift a load through a height. Its velocity ratio (VR) can be determined by:
VR = 
Note that for a practical wheel and axle, the radius of the wheel is greater than the radius of the axle.
Answer:
intensity of the light (the energy per unit area per unit time)
Explanation:
- The photoflash capacitor is an electrolytic capacitor that is also used in flash cameras, professional illumination and solid-state laser supply. Their general purpose is to briefly power a high-voltage flash tube, which can be used to illuminate photographic material or to alternately pump a laser rod.
- Since the flash tube requires very little time to operate, photoflash capacitors are designed to supply high discharge current pulses without excessive internal heating.
Answer:
The wire now has less (the half resistance) than before.
Explanation:
The resistance in a wire is calculated as:

Were:
R is resistance
is the resistance coefficient
l is the length of the material
s is the area of the transversal wire, in the case of wire will be circular area (
).
So if the lenght and radius are doubled, the equation goes as follows:

So finally because the circular area is a square function, the resulting equation is half of the one before.