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Dennis_Churaev [7]

3 years ago

15

What is the component called that usually has a dual-voltage selector switch and has cables that connect to the motherboard and

internal components?

1 answer:

MaRussiya [10]3 years ago

7 0

Answer:

"PSU (Power Supply Unit)" seems to be the correct approach.

Explanation:

The expression PSU comprises a system that controls as well as it across to components or modules within your PC. It transforms the AC power supply to various AC voltages that could be utilized to power the individual parts.
Perhaps it controls impedance to prevent spikes including surges typical to much other power equipment.

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(10 points) A single crystal in the titanium cable is oriented so that the [001] direction is parallel to the applied load. If t

Ulleksa [173]

Answer:yep

Explanation:

4 0

3 years ago

Water is flowing in a pipe. Which is the correct statement about the effect of an increase in the Reynolds number of the flow:

shepuryov [24]

Answer:

c.if the flow is laminar it could become turbulent.

Explanation:

The Reynolds number (Re) is a dimensionless quantity used to help predict flow patterns in different fluid flow situations. At low Reynolds numbers of below 2300 flows tend to be dominated by laminar, while at high Reynolds numbers above 4000, turbulence results from differences in the fluid's speed and direction. In between these values is the transition region of flow.

In practice, fluid flow is generally chaotic, and very small changes to shape and surface roughness of bounding surfaces can result in very different flows.

4 0

4 years ago

Identify the type of social responsibility discussed in the case with regard to

Schach [20]

Answer:

the types of social responsibility are as follows

1)Environmental Responsibility

2)Ethical Responsibility

3)Philanthropic Responsibility

4)Economic Responsibility

Social responsibility is an obligation every person has to do to uphold a balance among the economy as well as the environment. Social responsibility refers to maintain the balance between the environment and the budget.

It affects not only corporate governments but also everybody whose activity impacts the climate.

The Social responsibility towards the environment are as follows

1)Defend the environment, create balanced use of natural ingredients, and take important steps to stop pollution from the several processes adopted by the industries.

2)Encourage the viable use of raw resources and natural materials. Introduce strategies for continuously enlightening our environmental duty.

Introduce rules for continuous development in their ecological performance.

Obey with the law in force on conservational protection, and with other willingly recognized promises.

3)To encourage, by on-the-job practice, the participation of all our workers, independently and based on the team, in environmental safety problems.

4)To unite with the liable Agencies as well as Governmental Authorities.

To proceed with environmental protection courses.

5)To talk and report on our eco-friendly management struggles.

Implement and sustain the necessities of a Chain of Custody.

6)Stop trade and acquisition of illegally obtained wood.

7)Apply and continue a due industry system to avoid the acquisition and sale of criminally harvested timber and its products.

6 0

2 years ago

Why did my dad leave me yesterday like whatd i do?

Vsevolod [243]

Answer:

hmm i would try calling him. ask your mom or other adults where he is!

Explanation:

hope you get help soon!

4 0

3 years ago

An air-standard dual cycle has a compression ratio of 9.1 and displacement of Vd = 2.2 L. At the beginning of compression, p1 =

jok3333 [9.3K]

Answer:

a) T₂ is 701.479 K

T₃ is 1226.05 K

T₄ is 2350.34 K

T₅ is 1260.56 K

b) The net work of the cycle in kJ is 2.28 kJ

c) The power developed is 114.2 kW

d) The thermal efficiency, $\eta _{dual}$ is 53.78%

e) The mean effective pressure is 1038.25 kPa

Explanation:

a) Here we have;

$\frac{T_{2}}{T_{1}}=\left (\frac{v_{1}}{v_{2}} \right )^{\gamma -1} = \left (r \right )^{\gamma -1} = \left (\frac{p_{2}}{p_{1}} \right )^{\frac{\gamma -1}{\gamma }}$

Where:

p₁ = Initial pressure = 95 kPa

p₂ = Final pressure =

T₁ = Initial temperature = 290 K

T₂ = Final temperature

v₁ = Initial volume

v₂ = Final volume

$v_d$ = Displacement volume =

γ = Ratio of specific heats at constant pressure and constant volume cp/cv = 1.4 for air

r = Compression ratio = 9.1

Total heat added = 4.25 kJ

1/4 × Total heat added = $c_v \times (T_3 - T_2)$

3/4 × Total heat added = $c_p \times (T_4 - T_3)$

$c_v$ = Specific heat at constant volume = 0.718×2.821× 10⁻³

$c_p$ = Specific heat at constant pressure = 1.005×2.821× 10⁻³

v₁ - v₂ = 2.2 L

$\left \frac{v_{1}}{v_{2}} \right =r \right = 9.1$

v₁ = v₂·9.1

∴ 9.1·v₂ - v₂ = 2.2 L = 2.2 × 10⁻³ m³

8.1·v₂ = 2.2 × 10⁻³ m³

v₂ = 2.2 × 10⁻³ m³ ÷ 8.1 = 2.72 × 10⁻⁴ m³

v₁ = v₂×9.1 = 2.72 × 10⁻⁴ m³ × 9.1 = 2.47 × 10⁻³ m³

Plugging in the values, we have;

${T_{2}}= T_{1} \times \left (r \right )^{\gamma -1} = 290 \times 9.1^{1.4 - 1} = 701.479 \, K$

From;

$\left (\frac{p_{2}}{p_{1}} \right )^{\frac{\gamma -1}{\gamma }}= \left (r \right )^{\gamma -1}$ we have;

$p_{2} = p_{1}} \times \left (r \right )^{\gamma } = 95 \times \left (9.1 \right )^{1.4} = 2091.13 \ kPa$

1/4×4.25 = $0.718 \times 2.821 \times 10^{-3}\times (T_3 - 701.479)$

∴ T₃ = 1226.05 K

Also;

3/4 × Total heat added = $c_p \times (T_4 - T_3)$ gives;

3/4 × 4.25 = $1.005 \times 2.821 \times 10^{-3} \times (T_4 - 1226.05)$ gives;

T₄ = 2350.34 K

$\frac{T_{4}}{T_{5}}=\left (\frac{v_{5}}{v_{4}} \right )^{\gamma -1} = \left (\frac{r}{\rho } \right )^{\gamma -1}$

$\rho = \frac{T_4}{T_3} = \frac{2350.34}{1226.04} = 1.92$

$T_{5} = \frac{T_{4}}{\left (\frac{r}{\rho } \right )^{\gamma -1}}= \frac{2350.34 }{\left (\frac{9.1}{1.92 } \right )^{1.4-1}} =1260.56 \ K$

b) Heat rejected = $c_v \times (T_5 - T_1)$

$Therefore \ heat \ rejected = 0.718 \times 2.821 \times 10^{-3}\times (1260.56 - 290) = 1.966 kJ$

The net work done = Heat added - Heat rejected

∴ The net work done = 4.25 - 1.966 = 2.28 kJ

The net work of the cycle in kJ = 2.28 kJ

c) Power = Work done per each cycle × Number of cycles completed each second

Where we have 3000 cycles per minute, we have 3000/60 = 50 cycles per second

Hence, the power developed = 2.28 kJ/cycle × 50 cycle/second = 114.2 kW

d)

$Thermal \ efficiency, \, \eta _{dual} = \frac{Work \ done}{Heat \ supplied} = \frac{2.28}{4.25} \times 100 = 53.74 \%$

The thermal efficiency, $\eta _{dual}$ = 53.78%

e) The mean effective pressure, $p_m$ , is found as follows;

$p_m = \frac{W}{v_1 - v_2} =\frac{2.28}{2.2 \times 10^{-3}} = 1038.25 \ kPa$

The mean effective pressure = 1038.25 kPa.

3 0

4 years ago