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inna [77]
3 years ago
10

Which is the better buy, 6 bagels for $3.29 or 8 bagels for $4.15?

Mathematics
1 answer:
castortr0y [4]3 years ago
7 0
Well, we'd want to calculate the price of 1 bagel first.

To see which is better: divide $3.29 by 6 and then divide $4.15 by 8 and see which has the lowest answer.

The first option rounds off to $0.55 for one bagel. The second option rounds off to $0.52 for one bagel.

The second option is the best.
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Provide a recursive definition of the function f(n) = (n+1)!.
fiasKO [112]

Answer:

See definition below

Step-by-step explanation:

Since we have to give a recursive definition, we must give a initial value f(0). Additionally, the value of f(n) must depend on the value of f(n-1) for all n≥1.

The required value of f(0) is (0+1)!=1!=1.

Now, the factorial itself is a recursive function, because (n+1)!=(n+1)n!. In terms of f, this means that f(n)=(n+1)f(n-1) for all n≥1.

Then, our definition is: f:N→N is defined by

  1. f(0)=1.
  2. For n≥1, f(n)=(n+1)f(n-1).
8 0
3 years ago
Jim has $700 in savings at the beginning of summer. He wants to have at least
Julli [10]

Answer:

Jim has 700 and wants 300 left. he can spend 400. 25 every weekend. divide 400 by 25 and you get 16. the answer is 16

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Use the drawing tool(s) to form the correct answer on the provided graph.
Kitty [74]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

y> \frac{1}{4}x+6 ------>inequality A

The solution of the inequality A is the shaded area above the dashed line y=\frac{1}{4}x+6

The y-intercept of the dashed line is (0,6)

The x-intercept of the dashed line is (-24,0)

The slope of the dashed line is positive m=1/4

y> 2x-1 ------>inequality B

The solution of the inequality B is the shaded area above the dashed line y=2x-1

The y-intercept of the dashed line is (0,-1)

The x-intercept of the dashed line is (0.5,0)

The slope of the dashed line is positive m=2

The solution of the system of inequalities is the shaded area between the two dashed lines

using a graphing tool

see the attached figure

4 0
3 years ago
The radius of a nitrogen atom is 5.8*10^-11 meters, and the radius of a beryllium atom is 1.12*10^-10 meters. Which atom has a l
Burka [1]
Nitrogen Radius = 5.8 x 10⁻¹¹ m

Beryllium Radius = 1.12 x 10⁻¹⁰ m

Let's find the quotient of N/Be :

(5.8x10⁻¹¹)/(1.12x10⁻¹⁰). But 10⁻¹¹/10⁻¹⁰ = 10⁽⁻¹¹⁺¹⁰⁾ = 10⁻¹ = 1/10 = 0.1

→ (5.8/1.12).(0.1) = 0.58/1.12 = 0.518.

Conclusion: the radius of Be is almost double than the radius of N
5 0
3 years ago
Mr. Paulsen challenges Olivia and Angelica to move figure ABCDE onto figure A"B"C"D"E" using a series of two different transform
Jobisdone [24]

Problem 1

One method Olivia could have used is to reflect over the x axis and then translate 10 units to the right.

Let's apply these set of steps to point C.

C = (-2,-4)

C' = (-2,4) after reflecting over the x axis; y coordinate flips in sign

C'' = (8,4) after shifting to the right 10 units; add 10 to the x coordinate

Point C(-2,-4) moves to C''(8,4) which is shown in the diagram. I'll let you check the other four points.

-----------

Another method Olivia could have used is to shift to the right 10 units first, then reflect over the x axis. In this case, the order doesn't matter. Though for some other combinations of transformations, order does matter.

============================================================

Problem 2

Reflecting over the y axis will have the point (x,y) turn into (-x,y). Only the x coordinate changes, and we flip the sign here. The y coordinate stays the same.

A point like C(-2,-4) becomes C'(2,-4) after the y axis reflection. Shifting up 8 units means we add 8 to the y coordinate to arrive at C''(2,4) but this does not match what the diagram shows. Therefore, Angelica's method is incorrect.

You should find other inconsistencies for the other four points as well.

============================================================

Problem 3

Michael's method isn't correct either. He does not apply an x axis reflection and instead relies entirely on translations to move ABCDE to A''B''C''D''E''

At a quick glance, it looks like Michael may be correct. But upon a much closer look, you'll see that things don't line up perfectly.

Instead of point C, we'll pick on point D this time.

D is located at (-6,-2). If we shift up 8 units, then we add 8 to the y coordinate to get to D'(-6,6). Then add 10 to the x coordinate to shift 10 units to the right. This leads us to D''(4,6).

However, the diagram shows D'' is actually at (4,2)

I'll let you check the other points. You should find that only points C and E go to the correct locations, but the other points do not. Again, this is because Michael did not apply an x axis reflection. His figure of A''B''C''D''E'' is upside down compared to what it should be.

============================================================

To summarize, the methods described in problem 1 are the correct way to get ABCDE to move to A''B''C''D''E''. If Olivia followed either of those two methods, then she is correct. Both Angelica and Michael have incorrect methods.

5 0
3 years ago
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