It’s because flourecent lights operate at higher temperatures than incadecent lights.
Answer:
Work done = (1/2)[(Gmm_e)/(R_e)]
Explanation:
I've attached the explanations below.
Answer:
Explanation:
Energy E is conserved:
![E=\frac{1}{2}mv^2+mgh](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2%2Bmgh)
If v₀ = 22m/s, h₀=0m and h₁=25m:
![E=\frac{1}{2}mv_0^2=\frac{1}{2}mv_1^2+mgh_1](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1%7D%7B2%7Dmv_0%5E2%3D%5Cfrac%7B1%7D%7B2%7Dmv_1%5E2%2Bmgh_1)
Solving for v₁:
![v_1=\sqrt{v_0^2-2gh_1}](https://tex.z-dn.net/?f=v_1%3D%5Csqrt%7Bv_0%5E2-2gh_1%7D)
There is no real solution, because the stone never reaches 25m.
Answer:
v' = 1.5 m/s
Explanation:
given,
mass of the bullet, m = 10 g
initial speed of the bullet, v = 300 m/s
final speed of the bullet after collision, v' = 300/2 = 150 m/s
Mass of the block, M = 1 Kg
initial speed of the block, u = 0 m/s
velocity of the block after collision, u' = ?
using conservation of momentum
m v + Mu = m v' + M u'
0.01 x 300 + 0 = 0.01 x 150 + 1 x v'
v' = 0.01 x 150
v' = 1.5 m/s
Speed of the block after collision is equal to v' = 1.5 m/s