Answer:
0.338125 m/s
Explanation:
Applying,
Law of conservation of momentum
m'v' = mv............ Equation 1
Where m' = mass of the first skater, v' = velocity of the first skater, m = mass of the second skater, v = velocity of the second skater.
make v the subject of the equation
v = m'v'/m........... Equation 2
From the question,
Given: m' = 54.1 kg, v' = 0.375 m/s, m = 60 kg
Substitute these values into equation
v = (54.1×0.375)/60
v = 20.2875/60
v = 0.338125 m/s
