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3 years ago

How is me depressed or am me not? (but with a yoda voice)

Engineering

2 answers:

Murrr4er [49]3 years ago

5 0

Answer:

but the way is the way but the WAY is not the way

Explanation:

(yoda voice)

Rama09 [41]3 years ago

4 0

Answer:

umm am i supposed to be laughing?

Explanation:

sorryyy idk what yoda sounds like cuz i think star wars is pretty wack, just my opinion tho so dont get offended

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Two vehicles arrive at an uncontrolled intersection from different streets at the same time 1.The driver on the right must yield

ss7ja [257]

3. Both vehicles must stop

4 0

3 years ago

A heat engine that rejects waste heat to a sink at 520 R has a thermal efficiency of 35 percent and a second- law efficiency of

xeze [42]

Answer:

The source temperature is 1248 R.

Explanation:

Second law efficiency of the engine is the ratio of actual efficiency to the maximum possible efficiency that is reversible efficiency.

Given:

Temperature of the heat sink is 520 R.

Second law efficiency is 60%.

Actual thermal efficiency is 35%.

Calculation:

Step1

Reversible efficiency is calculated as follows:

$\eta_{II}=\frac{\eta_{a}}{\eta_{rev}}$

$0.6=\frac{0.35}{\eta_{rev}}$

$\eta_{rev}=0.5834$

Step2

Source temperature is calculated as follows:

$\eta_{rev}=1-\frac{T_{L}}{T}$

$\eta_{rev}=1-\frac{520}{T}$

$0.5834=1-\frac{520}{T}$

T = 1248 R.

The heat engine is shown below:

Thus, the source temperature is 1248 R.

6 0

3 years ago

I will Brainlist<br> "Burning and Inch". Describe this measurement.

MAVERICK [17]

Answer:

what measurement

Explanation:

8 0

3 years ago

Read 2 more answers

A work element in a manual assembly task consists of the following MTM-1 elements: (1) R16C, (2) G4A, (3) M10B5, (4) RL1, (5) R1

ella [17]

Answer:

1) R16C ; Tn = 17 TMU

2) G4A ; Tn = 7.3 TMU

3) M10B5 ; Tn = 15.1 TMU

4) RL1 ; Tn = 2 TMU

5) R14B ; Tn = 14.4 TMU

6) G1B ; Tn = 3.5 TMU

7) M8C3 ; Tn = 14.7 TMU

8) P1NSE ; Tn = 10.4 TMU

9) RL1 ; Tn = 2 TMU

b) 3.1 secs

Explanation:

a) Determine the normal times in TMUs for these motion elements

1) R16C ; Tn = 17 TMU

2) G4A ; Tn = 7.3 TMU

3) M10B5 ; Tn = 15.1 TMU

4) RL1 ; Tn = 2 TMU

5) R14B ; Tn = 14.4 TMU

6) G1B ; Tn = 3.5 TMU

7) M8C3 ; Tn = 14.7 TMU

8) P1NSE ; Tn = 10.4 TMU

9) RL1 ; Tn = 2 TMU

b ) Determine the total time for this work element in seconds

first we have to determine the total TMU = ∑ TMU = 86.4 TMU

note ; 1 TMU = 0.036 seconds

hence the total time for the work in seconds = 86.4 * 0.036 = 3.1 seconds

7 0

2 years ago

Design a fundamental mode asynchronous finite state machine that accepts input pair, A and B. The AB input sequence 00, 01,11, 1

dybincka [34]

Answer:

See explaination

Explanation:

A Finite state machines can be synchronous or asynchronous. The operation of asynchronous state machines does not require a clock signal. An Asynchronous state machine is classified basically on their operating mode, such as the fundamental mode, pulse mode or burst mode. An asynchronous state machine can have stable and transient states.

Please kindly refer to attachment for a step by step solution.

5 0

3 years ago