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k0ka [10]
3 years ago
8

How is me depressed or am me not? (but with a yoda voice)

Engineering
2 answers:
Murrr4er [49]3 years ago
5 0

Answer:

but the way is the way but the WAY is not the way

Explanation:

(yoda voice)

Rama09 [41]3 years ago
4 0

Answer:

umm am i supposed to be laughing?

Explanation:

sorryyy idk what yoda sounds like cuz i think star wars is pretty wack, just my opinion tho so dont get offended

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Refrigerant-134a at 700 kPa, 70°C, and 7.2 kg/min is cooled by water in a condenser until it exists as a saturated liquid at the
alex41 [277]

Answer:

The mass flow rate of cooling water required to cool the refrigerant is 123.788\,\frac{kg}{min}.

Explanation:

A condenser is a heat exchanger used to cool working fluid (Refrigerant 134a) at the expense of cooling fluid (water), which works usually at steady state. Let suppose that there is no heat interactions between condenser and surroundings.The condenser is modelled after the First Law of Thermodynamics, which states:

\dot Q_{ref} - \dot Q_{w} = 0

\dot Q_{ref} = \dot Q_{w}

\dot m_{ref}\cdot (h_{ref, in} - h_{ref,out}) = \dot m_{w}\cdot (h_{w, out} - h_{w,in})

The mass flow rate of the cooling water is now cleared:

\dot m_{w} = \dot m_{ref }\cdot \frac{h_{ref,in}-h_{ref,out}}{h_{w,out}-h_{w,in}}

Given that h_{ref,in} = 808.34\,\frac{kJ}{kg}, h_{ref, out} = 88.82\,\frac{kJ}{kg}, h_{w,out} = 104.83\,\frac{kJ}{kg} and h_{w,in} = 62.98\,\frac{kJ}{kg}, the mass flow of the cooling water is:

\dot m_{w} = \left(7.2\,\frac{kg}{min} \right)\cdot \left(\frac{808.34\,\frac{kJ}{kg}-88.82\,\frac{kJ}{kg} }{104.83\,\frac{kJ}{kg}-62.98\,\frac{kJ}{kg} } \right)

\dot m_{w} = 123.788\,\frac{kg}{min}

The mass flow rate of cooling water required to cool the refrigerant is 123.788\,\frac{kg}{min}.

4 0
3 years ago
Thermal energy storage systems commonly involve a packed bed of solid spheres, through which a hot gas flows if the system is be
hammer [34]

Answer:

A) i) 984.32 sec

ii) 272.497° C

B) It has an advantage

C) attached below

Explanation:

Given data :

P = 2700 Kg/m^3

c = 950 J/kg*k

k = 240 W/m*K

Temp at which gas enters the storage unit  = 300° C

Ti ( initial temp of sphere ) = 25°C

convection heat transfer coefficient ( h ) = 75 W/m^2*k

<u>A) Determine how long it takes a sphere near the inlet of the system to accumulate 90% of the maximum possible energy and the corresponding temperature at the center of sphere</u>

First step determine the Biot Number

characteristic length( Lc ) = ro / 3 = 0.0375 / 3 = 0.0125

Biot number ( Bi ) = hLc / k = (75)*(0.0125) / 40 = 3.906*10^-3

Given that the value of the Biot number is less than 0.01 we will apply the lumped capacitance method

attached below is a detailed solution of the given problem

<u>B) The physical properties are copper</u>

Pcu = 8900kg/m^3)

Cp.cu = 380 J/kg.k

It has an advantage over Aluminum

C<u>) Determine how long it takes a sphere near the inlet of the system to accumulate 90% of the maximum possible energy and the corresponding temperature at the center of sphere</u>

Given that:

P = 2200 Kg/m^3

c = 840 J/kg*k

k = 1.4 W/m*K

3 0
3 years ago
Which of the following parasites is also known as ascarids? Roundworms hookworms whipworms or ear mites?
Jet001 [13]

Answer: Roundworm,  hookworms, whipworms.

Explanation: Ascarids can be defined as any leaf insect or walking stick insect; phasmid nematode of the family Ascarididae.

They cause the disease ascariasis in humans and mammals and examples of them are roundworm, hookworm and whipworm.

4 0
3 years ago
A(n) _____ is done to test each individual component (often a program) to ensure that it is as defect-free as possible.
lyudmila [28]

Answer:

Unit test

Explanation:

Defintion: A test of each individual component (often a program) to ensure that it is as defect-free as possible.

6 0
2 years ago
Que os vizinhos diziam sempre aq lenhador? Responda com elementos do texto.​
Alecsey [184]

Answer:

shsisdnd ajwdhdjeo sisksdne suspended wowodndjd

4 0
3 years ago
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