Answer:
4. A concentration of a trace mineral was found to be 2.53 ppb in an aqueous solution. A. What mass of solution contains 2.53 g of the mineral? (1 point - Knowledge, 2 points - Inquiry, 1 point - Communication) m=? C = 2.53 ppm or 2.53X106 n = Con ܗ B. What volume of solution contains 2.53 g of the mineral? (1 point - Knowledge, 2 points - Inquiry, 1 point - Communication) VE? C: 2,53 ppm ns Cen
Answer: So if you had 570 cm of ribbon, then 570%2F8.5=67.05 which means that about 67 students can do the experiment (round down to the nearest whole number).
Explanation: If you had 8.5 cm of ribbon, then only 8.5%2F8.5=1 student can do the experiment. If you had 17 cm of ribbon, then 17%2F8.5=2 students can do the experiment.
Answer:
The answer is the letter A.
Explanation:
It is letter A because of Chlorine needs an electron to have a full shell. So, it will receive a negative one because it is gaining an electron. Potassium lost an electron because the element has to share the electron with Chlorine to balance its properties.
<u>Answer: </u>The volume of the solution is 85.7 mL
<u>Explanation:</u>
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
.....(1)
We are given:
Molarity of solution = 0.600 M
Given mass of
= 12.00 g
We know, molar mass of ![BaSO_4=[(1\times 137.33)+(1\times 32.07)+(4\times 16)]=233.4g/mol](https://tex.z-dn.net/?f=BaSO_4%3D%5B%281%5Ctimes%20137.33%29%2B%281%5Ctimes%2032.07%29%2B%284%5Ctimes%2016%29%5D%3D233.4g%2Fmol)
Putting values in equation 1, we get:

The rule of significant number that is applied for the problems having multiplication and division:
The least number of significant figures in any number of the problem determines the number of significant figures in the answer.
Here, the least number of significant figures is 3 that is determined by the number, 0.600. Thus, the answer must have these many significant figures only.
Hence, the volume of the solution is 85.7 mL
First of all the ethylamine is base so will be react with water to take the proton from the water (H⁺) , because water is amphoteric will react with bases as acid and acids as a base, so the water in this case will react as an acid and will gives the proton to the base.
In the picture you may see the chemical equation and the structure of the products.