All categories

3 years ago

Wich contains more humus topsoil or subsoil on number 18.

Chemistry

1 answer:

Nitella [24]3 years ago

6 0

Topsoil because plants and decaying animals add more humus to the soil

You might be interested in

The rate constant, k, for a first-order reaction is equal to 4.3 × 10-4 s-1. What is the half-life for the reaction? The rate co

pantera1 [17]

Answer:

1.6 × 10³ s

Explanation:

Let's consider the following generic reaction.

A → B

The rate law is:

$rate=k \times [A]^{m}$

where,

rate is the reaction rate

k is the rate constant

[A] is the molar concentration of the reactant A

m is the reaction order

When m = 1, we have a first-order reaction. We can calculate the half-life for this reaction using the following expression.

$t_{1/2}=\frac{ln2}{k} =\frac{ln2}{4.3 \times 10^{-4}s^{-1} }=1.6 \times 10^{3}s$

4 0

3 years ago

Use Gay-Lussac Law to solve. When the pressure of a balloon starts at 7.5 atm and the temperature surrounding the balloon goes f

ElenaW [278]

Answer:

The answer to your question is 6.77 atm

Explanation:

Data

Pressure 1 = P1 = 7.5 atm

Temperature 1 = T1 = 65°C

Pressure 2 = P2 = ?

Temperature 2 = T2 = 32°C

Process

-Use Gay-Lussac law to solve this problem

P1/T1 = P2/T2

-Solve for P2

P2 = P1T2 / T1

-Convert temperature to °K

T1 = 65 + 273 = 338°K

T2 = 32 + 273 = 305°K

-Substitution

P2 = (7.5 x 305) / 338

-Simplification

P2 = 2287.5 / 338

-Result

P2 = 6.77 atm

6 0

3 years ago

There are 0.55 moles of carbon dioxide gas in a 15.0 L container. This container is at a temperature of 300 K. What is the press

sertanlavr [38]

Answer:

$\large \boxed{\text{D.) 91 kPa}}$

Explanation:

We can use the Ideal Gas Law — pV = nRT

Data:

V = 15.0 L

n = 0.55 mol

T = 300 K

Calculation:

$\begin{array}{rcl}pV & =& nRT\\p \times \text{15.0 L} & = & \text{0.55 mol} \times \text{8.31 kPa$\cdot$ L$\cdot$K$^{-1}$mol$^{-1}\times$ 300 K}\\15.0p & = & \text{1370 kPa}\\p & = & \textbf{91 kPa}\end{array}\\\text{The pressure in the container is $\large \boxed{\textbf{91 kPa}}$}$