First, we have to get how many grams of C & H & O in the compound:
- the mass of C on CO2 = mass of CO2*molar mass of C /molar mass of CO2
= 0.5213 * 12 / 44 = 0.142 g
- the mass of H atom on H2O = mass of H2O*molar mass of H / molar mass of H2O
=0.2835 * 2 / 18 = 0.0315 g
- the mass of O = the total mass - the mass of C atom - the mass of H atom
= 0.3 - 0.142 - 0.0315 = 0.1265 g
Convert the mass to mole by divided by molar mass
C(0.142/12) H(0.0315/2) O(0.1265/16)
C(0.0118) H(0.01575) O(0.0079) by dividing by the smallest value 0.0079
C1.504 H3.99 O1 by rounding to the nearst fraction
C3/2 H4/1 )1/1 multiply by 2
∴ the emprical formula C3H8O2
Product are favored at ...
example 2A + 3B = 5C + D if reaction is exothermic ....delta H = NEGATIVE)
A decrease in temperature favors the forward reaction (more product formed)
as heat is considered as a product
For the exam I have given: A decrease in pressure (volume increases as pressure decreases) .... there are more number of moles on the product side (6 in all) .....so according to LCP decreasing pressure will revert back to increase pressure and to do that equilibrium position shifts to the right (product)
decreasing concentration of product will cause a disturbance in equilibrium position....and reaction will restore its equilibrium by shifting to the right
(I believe its like this)
Answer: All of these statements are true
Explanation:
Melting point help us to determine if a mixture is pure or has impurities by the virtues of it melting range..
Freezing point, boiling point, melting point, smell, attraction or repulsion to magnets, colour change, and many more examples.
Answer:
When the pressure increases to 90.0 atm , the volume of the sample is 0.01467L
Explanation:
To answer the question, we note that
P₁ = 1.00 atm
V₁ = 1.32 L
P₂ = 90 atm.
According to Boyle's law, at constant temperature, the volume of gas is inversely proportional to its pressure
That is P₁V₁ = P₂V₂
Solving the above equation for V₂ we have
that is V₂ = 
= 
or 0.01467L
