Answer:
CO is usually the abbreviation for company
Explanation:
Answer:
heater wattage = 4.32 kW
Explanation:
given data
volume flow rate of air = 0.1 m³/s
temperature t1 = 15°C
temperature t2 = 50°C
relative humidity RH = 80%
pressure = 101.325 kPa
to find out
heater wattage
solution
we will get here h value from psychometric chart with the help of temperature
that is
h1 = 37 kJ/kg
and
h2 = 73 kJ/kg
and v1 = 0.829 m³/kg
so here heater wattage formula is
heater wattage = m ( h2 -h1) ......1
here m is
m = V/v1 = 0.1 / 0.819 = 0.12 kg/s
so from equation 1
heater wattage = 0.12 ( 75 -39 )
heater wattage = 4.32 kW
Answer:
y=3
x=-8
Explanation:
<h3 />
2x+4y=-4 (x 3)
3x+5y=-3 (x -2)
6x+12y=-12 <em> (6x and</em>
-6x-10y=6 <em> -6x cancel)</em>
12y=-12 <em>(12y-10y)</em>
-10y=6 <em>(12-6)</em>
2y=-6
y=-6÷2=3 <em>(2 is brought across equals it divides)</em>
y=3 <em>(now replace 'y' in original equation with 3)</em>
2x+4(3)=-4 <em>(</em><em>4</em><em>×</em><em>3</em><em>=</em><em>1</em><em>2</em><em>)</em>
2x+12=-4
2x=-4-12 <em>(</em><em>12</em><em> </em><em>becomes</em><em> </em><em>-</em><em>12</em><em> </em><em>brought</em><em> </em><em>across</em><em> </em><em>equals</em><em>)</em>
2x=-16
x=-16÷2=-8 <em>(</em><em>multiply</em><em> </em><em>1</em><em>6</em><em> </em><em>across</em><em> </em><em>equals</em><em> </em><em>is</em><em> </em><em>divide</em><em> </em><em>16</em><em>)</em>
x=-8
*these are my workings on this equation, they may not be correct*
Answer:
The change in entropy = -0.6306 kJ/k
Explanation:
The mass of air = 2kg
In a Compressed isothermal process T₁ = T₂ = 27⁰ C
The initial pressure = 100 kPa
Final volume V₂ = 1/3 (V₁)
i.e. V₂/V₁ = 1/3
Rate ( gas constant) R = 0.287 kJ/kgk
The change in an entropy process is:
ΔS = m × R × In(V₂/V₁)
ΔS = 2 × 0,287 × In (1/3)
ΔS = -0.6306 kJ/k