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IgorLugansk [536]
4 years ago
8

Use the Lab screen to expand your ideas about what affects the landing location and path of a projectile. List any discoveries y

ou made to identify additional things that affect the landing site of a projectile and/or path of a projectile. Next to each item, briefly explain why you think the motion of the projectile is affected..
Physics
1 answer:
Snezhnost [94]4 years ago
7 0

Answer:

* air resistance.

*the direction of the rotation of the Earth

rotation of the thrown body

Explanation:

The projectile launch is described by the expressions

x-axis         x = v₀ₓ t

y-axis         y = v_{oy} t - ½ gt²

When the things that affect this movement are analyzed, in order of importance we have:

* air resistance. This significantly changes the body's horizontal position, so it introduces a horizontal acceleration that is not contained in the equations.

* air resistance. At the height that the body reaches, since air resistance has the same direction as the gravity of gravity and therefore the relationship is more challenging.

* to a lesser extent the direction of launch, in the direction of the rotation of the Earth against. Since this creates an operational on the x and y axis that changes the initial assumption

* The possible rotation of the thrown body, since this rotation creates a lift that is not taken in the equations, this value is more noticeable the lighter the body, this effect has to keep the body longer in the air achieving more reach and height

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A 20 watt light bulb is left burning inside a refrigerator operating on a reverse Carnot cycle. If the refrigerator also draws 2
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Explanation:

Given that,

Power drawn by the refrigerator = 20 watt

Power of burning light inside = 20 watt

Room temperature = 27°C

We need to calculate the temperature

Using formula of coefficient of refrigerator

COR_{R}=\dfrac{Q_{c}}{W}

\dfrac{Q_{c}}{W}=\dfrac{T_{c}}{T_{H}-T_{c}}

Put the value into the formula

\dfrac{20}{20}=\dfrac{T_{c}}{T_{H}-T_{c}}

\dfrac{T_{c}}{T_{H}-T_{c}}=1

T_{h}=2T_{c}

T_{c}=\dfrac{T_{h}}{2}

T_{c}=\dfrac{27+273}{2}

T_{c}=150\ K

T_{c} is less than T_{h}

Therefore, refrigerator cools its interior below room temperature while the bulb is on.

Hence, This is the required solution.

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4 years ago
Which one of these is true about forces
zvonat [6]

Answer: D

Explanation:

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2 years ago
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Two children of mass 20.0 kg and 30.0 kg sit balanced on a seesaw with the pivot point located at the center of the seesaw. If t
s2008m [1.1K]

Answer:

The distance from the pivot point that the small child will sit in order to maintain the balance is 1.8 m

Explanation:

Given;

mass of the bigger child, M = 30 kg

mass of the smaller child, m = 20 kg

distance between the two children, d = 3 m

This information can be represented diagrammatically;

                                    3m

         |<------------------------------------------------>|

----------------------------------------------------------------------------

         ↓             x            Δ            3-x           ↓

         20kg                                                 30kg

x is the distance from the pivot point that the small child will sit in order to maintain the balance

Take moment about the pivot;

Clockwise moment = anticlockwise moment

30(3-x) = 20x

90 -30x = 20x

90 = 20x + 30x

90 = 50x

x = 90 / 50

x = 1.8 m

Therefore, the distance from the pivot point that the small child will sit in order to maintain the balance is 1.8 m

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3 years ago
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Answer:

Say you feel like you twisted ur ankle or can move your foot or something in that category

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3 years ago
Consider Compton Scattering with visible light.A photon with wavelength 500nm scatters backward(theta=180degree) from a free ele
JulijaS [17]

Answer: 4.86(10)^{-12}m

Explanation:

The Compton Shift \Delta \lambda in wavelength when photons are scattered is given by the following equation:

\Delta \lambda=\lambda' - \lambda_{o}=\lambda_{c}(1-cos\theta) (1)  

Where:  

\lambda'=500 nm=500(10)^{-9} m is the wavelength of the scattered photon

\lambda_{o}  is the wavelength of the incident photon

\lambda_{c}=2.43(10)^{-12} m is a constant whose value is given by \frac{h}{m_{e}.c}, being h=4.136(10)^{-15}eV.s the Planck constant, m_{e} the mass of the electron and c=3(10)^{8}m/s the speed of light in vacuum.  

\theta=180\° the angle between incident phhoton and the scatered photon.  

\Delta \lambda=2.43(10)^{-12} m (1-cos(180\°)) (2)

\Delta \lambda=4.86(10)^{-12}m (3)  This is the shift in wavelength

5 0
3 years ago
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