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2 years ago

What kind of energy is required for photosynthesis to occur?

Chemistry

1 answer:

MrMuchimi2 years ago

5 0

A. Solar Energy

Hope this helps!
STSN

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1234567 sc: thatbitxh.lizzy

sesenic [268]

Answer:

okyay

Explanation:

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2 years ago

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Which of the following is NOT a homogeneous mixture? *<br> koolaid<br> soda<br> tea<br> water

Wittaler [7]

Answer:

water

Explanation:

Because it does not have more than one component.

4 0

2 years ago

Please I need help with questions 5-9 and it’s very hard and I’m struggling with it and if you need to see the picture big then

Serggg [28]

"the answer will be 0.00 "

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2 years ago

A sound wave is traveling at 331 m/s and has a frequency of 126 Hz. What is the wavelength?

damaskus [11]

<h2>Answer</h2>

2.626984127 m

<h2>Explanation:</h2><h2></h2>

You have to know the equation that relates wavelength, frequency, and velocity (it's like speed but a bit different).

v = f x λ

where:

v = velocity

f = frequency

λ = Wavelength

Rearrange to make λ subject:

λ = v / f

We've been given 331 as the speed, 126 as the frequency. Sub it into the equation:

331 / 126 = 2.626984127 m

3 0

2 years ago

What is the composition, in atom percent, of an alloy that consists of a) 5.5 wt% Pb and b) 94.5 wt% of Sn? Assume that the atom

Anastaziya [24]

Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

Explanation :

First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.

As, 207.2 g of lead contains $6.022\times 10^{23}$ atoms

So, 5.5 g of lead contains $\frac{5.5}{207.2}\times 6.022\times 10^{23}=1.59\times 10^{22}$ atoms

and,

As, 118.71 g of lead contains $6.022\times 10^{23}$ atoms

So, 94.5 g of lead contains $\frac{94.5}{118.71}\times 6.022\times 10^{23}=4.79\times 10^{23}$ atoms

Now we have to calculate the percent composition of Pb and Sn in atom.

$\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%$

and,

$\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%$

Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

6 0

3 years ago