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ss7ja [257]
3 years ago
11

How many grams of titanium could be obtained from a 27.00 mole sample of Ti6Al4V?

Chemistry
2 answers:
Yakvenalex [24]3 years ago
7 0

#7754.9g#

If the sample was measured in grams, we would first need to convert it to moles and then determine the amount of titanium. Because we already have the sample in a molar quantity, the moles of titanium is simply the formula ratio – 6 moles of titanium per mole of compound.
So, we have #6 xx 27 = 162# moles of titanium. Converting this to mass from the gram molecular weight, we obtain is
#162 xx 47.87 = 7754.9g#
Marianna [84]3 years ago
7 0

Answer:

7754 g

Explanation:

According to the chemical formula, in 1 mole of Ti₆Al₄V, there are 6 moles of titanium. The moles of titanium in 27.00 moles of Ti₆Al₄V are:

27.00 mol Ti₆Al₄V × (6 mol Ti/1 mol Ti₆Al₄V) = 162.0 mol Ti

The molar mass of titanium is 47.867 g/mol. The mass corresponding to 162.0 moles is:

162.0 mol × (47.867 g/mol) = 7754 g

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In the reaction Pb + 2Ag+ – Pb2+ + 2Ag, the Ag+ is.
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<h2><u>Question :-</u></h2>

In the reaction Pb + 2Ag+ – Pb2+ + 2Ag, the Ag+ is.

a) Reduced, and the oxidation number changes from +1 to 0.

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c) Oxidized and the oxidation number changes from 0 to +1.

d) Oxidized, and the oxidation number changes from +1 to 0.

<h3>____________________</h3>

<h2><u>Solution :-</u></h2>

<h3><u>Given Information :-</u></h3>

  • <u>Reaction ➢</u> Pb + 2Ag⁺ ⟶ Pb²⁺ + 2Ag

<h3><u>To Find :-</u></h3>

  • Whether Ag⁺ is:-

  • a) Reduced, and the oxidation number changes from +1 to 0.

  • b) Reduces and the oxidation number changes from +2 to 0.

  • c) Oxidized and the oxidation number changes from 0 to +1.

  • d) Oxidized, and the oxidation number changes from +1 to 0.

<h3><u>Answer :-</u></h3>

Firstly let us know the meaning of Oxidation & Reduction and Oxidizing & Reducing Agent :-

  1. Oxidation is process of loss of electron(s). Either atom or ion undergoing oxidation, is known as reducing agent.
  2. Reduction is process of gain of electron(s). Either atom or ion undergoing reduction, is known as oxidizing agent.

In this reaction, Ag⁺ gains an electron to get <u>reduced</u> to Ag. The oxidation number changes from +1 to 0. Therefore, Ag+ is an oxidizing agent.

Since, this possibility is given in option a). Reduced, and the oxidation number changes from +1 to 0. Hence, option a is the correct answer.

<h3>____________________</h3>

<h2><u>Final Answer :-</u></h2>

  • Option a. Reduced, and the oxidation number changes from +1 to 0 is correct answer.

<h3>____________________</h3>
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