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ss7ja [257]
3 years ago
11

How many grams of titanium could be obtained from a 27.00 mole sample of Ti6Al4V?

Chemistry
2 answers:
Yakvenalex [24]3 years ago
7 0

#7754.9g#

If the sample was measured in grams, we would first need to convert it to moles and then determine the amount of titanium. Because we already have the sample in a molar quantity, the moles of titanium is simply the formula ratio – 6 moles of titanium per mole of compound.
So, we have #6 xx 27 = 162# moles of titanium. Converting this to mass from the gram molecular weight, we obtain is
#162 xx 47.87 = 7754.9g#
Marianna [84]3 years ago
7 0

Answer:

7754 g

Explanation:

According to the chemical formula, in 1 mole of Ti₆Al₄V, there are 6 moles of titanium. The moles of titanium in 27.00 moles of Ti₆Al₄V are:

27.00 mol Ti₆Al₄V × (6 mol Ti/1 mol Ti₆Al₄V) = 162.0 mol Ti

The molar mass of titanium is 47.867 g/mol. The mass corresponding to 162.0 moles is:

162.0 mol × (47.867 g/mol) = 7754 g

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Explanation:

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The valence electrons in an atom are the outermost shell electrons. They are the most loosely held electrons in an atom.

Coincidentally, the periodic table of elements divided into vertical groups and horizontal periods can be said to be arranged according to the number of valence electrons.

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3. explain how you know the number of valence electrons for each group.

The number of valence electrons in a group is the group number:

   Group      Number                     valence electrons

              1A                                                 1

              2A                                                2

              3A                                                 3

              4A                                                 4

               5A                                                5

               6A                                                6

               7A                                                7

               8A                                                8

learn more:

Periodic table brainly.com/question/1971327

#learnwithBrainly

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skelet666 [1.2K]

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6 0
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3 0
3 years ago
How many grams of chlorine gas can be produced when 50.0 grams of aluminum chloride decompose? 2AlCl3→ 2Al + 3Cl2
lianna [129]

Answer:

Explanation:

Approx.

425

⋅

g

Explanation:

2

A

l

(

s

)

+

3

C

l

2

(

g

)

→

2

A

l

C

l

3

(

s

)

You have given a stoichiometrically balanced equation, so bravo.

The equation explicitly tells us that

54

⋅

g

of aluminum metal reacts with

6

×

35.45

⋅

g

C

l

2

gas to give

266.7

⋅

g

of

aluminum trichloride

hope this helps

6 0
3 years ago
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