Balanced chemical reaction: 2S + 3O₂ → 2SO₃.
1) Answer is: oxygen is limiting reactant.
n(S) = 3 mol; amount of sulfur.
n(O₂) = 4 mol; amount of oxygen.
From balanced chemical reaction: n(S) : n(O₂) = 2 : 3.
3 mol : n(O₂) = 2 : 3.
n(O₂) = (3 · 3 mol) ÷ 2.
n(O₂) = 4.5 mol; limiting reactant, because there is only 4 mol of oxygen.
2) Answer is: sulfur(S) is limiting reactant.
n(S) = 3 mol.
n(O₂) = 5 mol.
From balanced chemical reaction: n(S) : n(O₂) = 2 : 3.
n(S) : 5 mol = 2 : 3.
n(S) = 10 mol ÷ 3.
n(S) = 3.33 mol; there is only 3 mol of sulfur, so it is not enough.
3) Answer is: oxygen (O₂) is limiting reactant.
n(S) = 3 mol.
n(O₂) = 3 mol.
From balanced chemical reaction: n(S) : n(O₂) = 2 : 3.
3 mol : n(O₂) = 2 : 3.
n(O₂) = (3 · 3 mol) ÷ 2.
n(O₂) = 4.5 mol; limiting reactant, because there is only 3 mol of oxygen.
1 empty cup is equal to 8 OZ
4 empty cups is equal to 32 OZ
Answer:
Final temperature = T₂ = 328.815 K
Explanation:
Given data:
Given energy = 980 KJ = 980×1000= 980000 J
Volume = 6.2 L
Initial temperature =T₁= 291 K
Specific heat of water = 4.18 j /g .K
Final temperature = T₂ = ?
Formula:
Q = m. c . ΔT
ΔT = T₂ - T₁
we will first convert the litter into milliliter
6.2 × 1000 = 6200 mL
It is given in question that
1 mL = 1 g
6200 mL = 6200 g
Now we will put the values in formula,
Q = m. c . (T₂ - T₁)
980000 j = 6200 g . 4.18 j /g .K . (T₂ - 291 K)
980000 j = 25916 j/ k . (T₂ - 291 K)
980000 j / 25916 j/ k = T₂ - 291 K
37.8145 K + 291 K =T₂
T₂ = 328.815 K
Gynosperms is a plant that has seeds unprotected by an ovary or fruit and Gymnosperms include the conifers and cycads and angiosperms are a plant that has flowers and produces seeds enclosed within a carpel. The angiosperms are a large group and include herbaceous plants, shrubs, and most trees.
