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vekshin1
4 years ago
14

water at 400 kPa and 60°C while the other part is evacuated. The partition is now removed, and the water expands to fill the ent

ire tank. Determine the entropy change of water during this process, if the final pressure in the tank is 40 kPa
Chemistry
1 answer:
kaheart [24]4 years ago
6 0

Answer:

0.4912 kJ/K

Explanation:

Using steam table, the properties of water at stage 1 can be determined:

P_{1} = 400 kPa

T_{1} = 60°C

Therefore, from steam table:

specific volume v_{1}  = 0.001017 m^{3}/kg

entropy  s_{1}  = 0.8313 kJ/kg*K

Calculating the specific volume of water after the partition is removed, since the mass is constant and volume of water is doubled:

v_{2} = 2*0.001017 = 0.002034 m^{3}/kg

Final pressure of water in the tank = P_2} = 40 kPa

dryness factor after removing the partition

x = \frac{0.002034 - 0.001026}{3.993 - 0.001026} = 2.524*10^{-4} kg/vapor

Therefore:

s_{2} = s_{f2} + x*s_{fg2}  = 1.0261 + (2.524*10^{-4}*6.643) = 1.02778 kJ/kg*K

Thus, the entropy change is:

Δs = m*(s_{2}-s_{1}) = 2.5*(1.02778 - 0.8313) = 0.4912 kJ/K

Therefore, the entropy change of water is 0.4912 kJ/K

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