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Inga [223]
2 years ago
13

575 394 9550 bFzN0S come study with me!

Chemistry
2 answers:
ch4aika [34]2 years ago
8 0

Answer:

Oo oki

Explanation:

Rina8888 [55]2 years ago
7 0

Answer:

im good thxs for offering tho!

Explanation:

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How many moles in 2.0g of carbon dioxide?
ANEK [815]
First you need to find out the Limiting reactant (LR). convert both reactants to the same thing. Check that the chemical equation is balanced.  Now use stoichiometr and remember at moles, multiply: need moles, divide2 g / 42g/mol=  0.0477 mol propane         mass propane/ Molar Mass propane = moles propane4 g / 32 g/mol= 0.125 mol oxygen X (1 mol/ 5 mol) = 0.025 mol propane   oxygen is the LRmass O2 / MM O2 X (mol propane / mol O2)0.025 mol X (3 mol / 1 mol ) = .075 mol CO20.075 mol X (12 + 2*16) g /mol = 3.6 g CO2 In one step:2 g / 42g/mol X (3 mol / 1 mol ) X 48 g/mol = 6.86 g CO24 g / 32 g/mol X (3 mol / 5 mol ) X 48 g/mol = 3.6 g CO2mass/ MM        X coefficient ratio  X MM (new)
4 0
3 years ago
Which has a higher melting point KF or KI?
NeX [460]

Answer:

kf

Explanation:

5 0
3 years ago
A 3.0 g sample of a gas occupies a volume of 1.00L at 100C and 740 torr pressure. The molecular weight of the
SOVA2 [1]

Answer:

94.2 g/mol

Explanation:

Ideal Gases Law can useful to solve this

P . V = n . R . T

We need to make some conversions

740 Torr . 1 atm/ 760 Torr = 0.974 atm

100°C + 273 = 373K

Let's replace the values

0.974 atm . 1 L = n . 0.082 L.atm/ mol.K . 373K

n will determine the number of moles

(0.974 atm . 1 L) / (0.082 L.atm/ mol.K . 373K)

n = 0.032 moles

This amount is the weigh for 3 g of gas. How many grams does 1 mol weighs?

Molecular weight → g/mol → 3 g/0.032 moles = 94.2 g/mol

3 0
3 years ago
Which of these is a body fossil?<br> A.shrimp burrow B.Plant Imprint C. Claw Print D.dinousaur egg
Alik [6]
Claw print could be it
3 0
3 years ago
Read 2 more answers
There are two isotopes of an unknown element, X-19 and X-21. The abundance of X-19 is 14.55%. A weighted average uses the percen
alekssr [168]

Answer:

2.765amu is the contribution of the X-19 isotope to the weighted average

Explanation:

The average molar mass is defined as the sum of the molar mass of each isotope times its abundance. For the unknown element X that has 2 isotopes the weighted average is defined as:

X = Mass X-19 * Abundance X-19 + MassX-21 * Abundance X-21

The contribution of the X-19 isotope is its mass (19.00 amu) times its abundance (14.55% = 0.1455). That is:

19.00amu * 0.1455 =

2.765amu is the contribution of the X-19 isotope to the weighted average

8 0
2 years ago
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