compare the arrangement of atoms or molecules in an amorphous solid to the arrangement of atoms or molecules in a crystalline so
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Answer:
The net Electric field at the mid point is 289.19 N/C
Given:
Q = + 71 nC =
Q' = + 42 nC =
Separation distance, d = 1.9 m
Solution:
To find the magnitude of electric field at the mid point,
Electric field at the mid-point due to charge Q is given by:
Now,
Electric field at the mid-point due to charge Q' is given by:
Now,
The net Electric field is given by:
To solve this problem we will apply the concepts related to the balance of Forces, the centripetal Force and Newton's second law.
I will also attach a free body diagram that allows a better understanding of the problem.
For there to be a balance between weight and normal strength, these two must be equivalent to the centripetal Force, therefore
Here,
m = Net mass
= Angular velocity
r = Radius
W = Weight
N = Normal Force
The net mass is equivalent to
Then,
Replacing we have then,
Solving to find the angular velocity we have,
Therefore the angular velocity is 0.309rad/s