(1) The time of motion of the arrow is 0.25 s.
(2) The vertical height dropped by the arrow as it approaches the target is 0.31 m.
The given parameters:
- <em>Horizontal distance of the arrow, X = 20 m</em>
- <em>Horizontal speed of the arrow, v = 80 m/s</em>
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The time of motion of the arrow is calculated as follows;
The vertical height dropped by the arrow as it approaches the target is calculated as follows;
Learn more about time of motion of projectile here: brainly.com/question/1912408
195 is the rounded atomic atomic mass of platinum
Answer:
14.2
Explanation:
find horizontal force of the weight = 2.5kg x 9.8 Sin30 = 12.3 N
to prevent the sliding she needs to pull horizontally
Fh = 12.3 /Cos 30 =14.2N
Based on scientific records, a charm quark has a charge that's approximately equal to: 2) 1.07 × 10⁻¹⁹ C.
<h3>What is a charge?</h3>
A charge simply refers to a fundamental, physical property of matter that governs how the particles of a substance are affected by an electromagnetic field, especially due to the presence of an electrostatic force (F).
Also, charge is typically measured in Coulombs and a charm quark (elementary particle) has a charge that's approximately equal to 1.07 × 10⁻¹⁹ Coulomb.
Read more on charges here: brainly.com/question/4313738
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Answer:
d)
Explanation:
Newton's 3rd Law tells us that for every action we will have a reaction equal in magnitude and opposite in direction. In a collision between obects A and B this means that the force on A applied by B will be equal in magnitude than the force on B applied by A, which leaves d as the true answer and the rest as false.
