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2 years ago

87) Determine the equivalent resistances for the following circuits.

Physics

1 answer:

stepladder [879]2 years ago

8 0

Answer:

15 and 11 ohms

Explanation:

First one = For the parallel resistors 1 / (1/6 + 1/6 + 1/6) = 1/ (3/6 ) = 6/3 = 2 ohms then add the 3 and the 10 = 15 ohms

second one for the parallel portion equiv = (10+2)*24 / ( (10+2 + 24) = 8

then add the 3 in series = 11 ohms

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3 years ago

a cyclist must travel 800 km. how many days will the trip take if the cyclist travels 8/h day at an average speed of 16km/h

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3 years ago

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kotykmax [81]

Answer:

a) $v=1.77\times 10^6\ m/s$

b) $v=3.872\times 10^6\ m/s$

c) $v=5.5\times 10^6\ m/s$

d) $v=6.7\times 10^6\ m/s$

e) $v=7.7\times 10^6\ m/s$

Explanation:

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$a=\dfrac{q.V}{m.d}$ ---------1

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$m=9.1\times 10^{-31}\ kg$

The charge on electron

$q=1.6\times 10^{-19}\ C$

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$a=\dfrac{1.6\times 10^{-19}\times 200}{9.1\times 10^{-31}\times 0.02}\ m/s^2$

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We know that

$v^2=u^2+2as$

s = 0.1 cm

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$v=\sqrt{3.16\times 10^{12}}\ m/s$

$v=1.77\times 10^6\ m/s$

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$v^2=(4\times 10^5)^2+2\times 1.5\times 10^{15}\times 0.5\times 10^{-2}$

$v=\sqrt{1.5\times 10^{13}}\ m/s$

$v=3.872\times 10^6\ m/s$

s = 1 cm

$v^2=(4\times 10^5)^2+2\times 1.5\times 10^{15}\times 1\times 10^{-2}$

$v=\sqrt{3.06\times 10^{13}}\ m/s$

$v=5.5\times 10^6\ m/s$

s = 1.5 cm

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s = 2 cm

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$v=\sqrt{6.06\times 10^{13}}\ m/s$

$v=7.7\times 10^6\ m/s$

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mixer [17]

Hi there!

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$\large\boxed{\Sigma F = ma}$

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Δv = 3 m/s

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