Answer:
Efficiency based on Otto cycle.
Effotto = 47.47%
Explanation:
Efficiency based on Otto cycle.
effotto = 1 – (V2 / V1)^γ-1
effotto = 1 – (1 / 5)^1.4 - 1
effotto = 47.47%
The correct answer is A
Faraday and Weber
:)
Answer:
Test code:
>>u=10;
>>g=9.8;
>>q=100;
>>m0=100;
>>vstar=10;
>>tstar=fzero_rocket_example(u, g, q, m0, vstar)
Explanation:
See attached image