Answer:

Explanation:
given data:
pressure 1 MPa
diameter of pipe = 30 cm
average velocity = 10 m/s
area of pipe

A = 0.070 m2
WE KNOW THAT mass flow rate is given as

for pressure 1 MPa, the density of steam is = 4.068 kg/m3
therefore we have


Answer:
See explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem.
Answer:
The attached figure shows the hydraulic circuit using one sequence valve to control two simultaneous operations performed in proper sequence in one direction only. In the other direction, both the operations are simultaneous.
When we keep the 4/2 DCV in crossed arrow position, oil under pressure is supplied to the inlet port of the sequence valve. It directly flows to Head end port-1. Hence Cylinder 'C1' extends first.
By the end of the extension of cylinder 'C1', pressure in the line increases and hence poppet of sequence valve is lifted off from its seat and allows oil to flow to port-2 and hence, Cylinder 'C2 extends completing the pressing operation.
In the straight-arrow position of 4/2 DCV the oil under pressure reaches the rod end of both the cylinders C1 and C2 simultaneously through port-3. This causes both the cylinders to retract simultaneously.
Also, a Flow control valve is provided tho control the velocity of clamping
Explanation:
find attached the figure
Answer:
Q=67.95 W
T=119.83°C
Explanation:
Given that
For air
Cp = 1.005 kJ/kg·°C
T= 20°C
V=0.6 m³/s
P= 95 KPa
We know that for air
P V = m' R T
95 x 0.6 = m x 0.287 x 293
m=0.677 kg/s
For gas
Cp = 1.10 kJ/kg·°C
m'=0.95 kg/s
Ti=160°C ,To= 95°C
Heat loose by gas = Heat gain by air
[m Cp ΔT] for air =[m Cp ΔT] for gas
by putting the values
0.677 x 1.005 ( T - 20)= 0.95 x 1.1 x ( 160 -95 )
T=119.83°C
T is the exit temperature of the air.
Heat transfer
Q=[m Cp ΔT] for gas
Q=0.95 x 1.1 x ( 160 -95 )
Q=67.95 W
Explanation:
a) The total volume equals the sum of the volumes.
500 = x + y
The total octane amount equals the sum of the octane amounts.
89(500) = 87x + 92y
44500 = 87x + 92y
b) desmos.com/calculator/ekegkzllqx
As x increases, y decreases.
c) Use substitution or elimination to solve the system of equations.
44500 = 87x + 92(500−x)
44500 = 87x + 46000 − 92x
5x = 1500
x = 300
y = 200
The required volumes are 300 gallons of 87 gasoline and 200 gallons of 92 gasoline.