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Bumek [7]
3 years ago
11

A continuous and aligned fiber-reinforced composite having a cross-sectional area of 1130 mm2is subjected to an external tensile

load. If the stresses sustained by the fiber and matrix phases are 156 MPa and 2.75 MPa, respectively, the force sustained by the fiber phase is 74,000 Nand the total longitudinal strain is1.25x 10-3, determine (a)the force sustained by the matrix phase, (b)the modulus of elasticity of the composite material in the longitudinal direction, and (c)the moduli of elasticity for the fiber and matrix phases.

Engineering
1 answer:
lakkis [162]3 years ago
8 0

Answer:

(a)  The force sustained by the matrix phase is 1802.35 N

(b) The modulus of elasticity of the composite material in the longitudinal direction Ed is 53.7 GPa

(c) The moduli of elasticity for the fiber and matrix phases is 124.8 GPa and 2.2 GPa respectively

Explanation:

Find attachment for explanation

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Answer:

Q=127.66W

L=9.2mm

Explanation:

Heat transfer consists of the propagation of energy in the form of heat in different ways, these can be convection if it is through a fluid, radiation through electromagnetic waves and conduction through solid solids.

To solve any problem related to heat transfer, the general equation is used

Q = delta / R

Where

Q = heat

Delta = the temperature difference

R = is the thermal resistance by conduction, convection and radiation

to solve this problem we propose the previous equation

Q = delta / R

later we find R

R=[tex]r=\frac{6L1}{AK1} +\frac{5L2}{AK2}+\frac{1}{Ah}

R=\frac{6(0.0001)}{(1.25)(0.026)} +\frac{5(0.012)}{(1.25)(0.026)}+\frac{1}{(25)(1.25)} =0.235 K/w

Q=(25-(-5))/0.235=127.66W

part b

we use the same ecuation with Q=127.66

Q = delta / R

ΔR=\frac{L}{KA} +\frac{1}{hA} \\R=\frac{L}{(0.035)(1.25)} +\frac{1}{(25)(1.25)}\\ R=22.85L+0.032\\Q=(T1-T2)/R\\\\127.66=(25-(-5))/(22.85L+0.032)\\solving for L\\L=9.2mm

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3 years ago
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