Answer:
P_2 =0.51 atm
Explanation:
Given that:
Volume (V1) = 2.50 L
Temperature (T1) = 298 K
Volume (V2) = 4.50 L
at standard temperature and pressure;
Pressure (P1) = 1 atm
Temperature (T2) = 273 K
Pressure P2 = ??
Using combined gas law:




ANSWER: receptor-meditated endocytosis
I’m not sure if this is what you’re looking for but this is correct. Next time please add the full question and possible answers. HOPE this helps someone please leave thanks if so.
What is the exoeruent. Searched it up on google and only came up with two search results. None related to chemistry
Answer : The volume of
produced at standard conditions of temperature and pressure is 0.2422 L
Explanation :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,

where,
= initial pressure of
gas = (740-22.4) torr = 717.6 torr
= final pressure of
gas at STP= 760 torr
= initial volume of
gas = 280 mL
= final volume of
gas at STP = ?
= initial temperature of
gas = 
= final temperature of
gas = 
Now put all the given values in the above equation, we get:


Therefore, the volume of
produced at standard conditions of temperature and pressure is 0.2422 L