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Anton [14]
3 years ago
10

Why is the specific heat of salt solution lower than that of water?

Physics
1 answer:
Stells [14]3 years ago
3 0
When we dissolve NaCl in water, the ions are held in a rigid cage of water molecules. It takes less energy to activate these molecules, so the specific heat of the water decreases. The greater concentration of NaCl, the lower the specific heat capacity of the solution.
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The sticky substances in cigarettes that coat the lining of the<br> lungs are _____.
Svetach [21]

Answer:

Tar

Explanation: Tar is a big ingredient in cigarettes and can cause the sticky substance

5 0
3 years ago
Read 2 more answers
Suppose that a sound source is emitting waves uniformly in all directions. If you move to a point twice as far away from the sou
Helen [10]

Answer:

<em>d. unchanged.</em>

Explanation:

The frequency of a wave is dependent on the speed of the wave and the wavelength of the wave. The frequency is characteristic for a wave, and does not change with distance. This is unlike the amplitude which determines the intensity, which decreases with distance.

In a wave, the velocity of propagation of a wave is the product of its wavelength and its frequency. The speed of sound does not change with distance, except when entering from one medium to another, and we can see from

v = fλ

that the frequency is tied to the wave, and does not change throughout the waveform.

where v is the speed of the sound wave

f is the frequency

λ is the wavelength of the sound wave.

4 0
3 years ago
The intensity level of a "Super-Silent" power lawn mower at a distance of 1.0 m is 100 dB. You wake up one morning to find that
Gala2k [10]

Answer:

The intensity level in the room is 63 dB

Explanation:

To calculate the intensity of sound in the room, we use the equation of definition of decibels

     β = 10 log (I / Io)      (1)

With “I” the sound intensity and “Io” the threshold intensity 1.0 10⁻⁻¹² W/m²

To calculate the intensity we will use the initial data and remember the power of the emitted sound is constant, in addition that the sound propagates in three-dimensional form or on a spherical surface

      I = P/A    ⇒    P = I A

The area of ​​a sphere is 4 π r², where I can calculate of 1

     β/10 = log (I/Io)

   I / Io = {10}^{\beta /10}

   I = Io  {10}^{\beta /10}

   I = 1 10⁻¹² 10⁽¹⁰⁰/¹⁰⁾   = 1 10⁻¹² 10¹⁰

   I = 1.0 10⁻² W

With this we can calculate the intensity for a distance of 20 m

 I  = 1.0 10⁻² / ( 4π 20²)

 I =  2.0 10⁻⁶ W/m²

We have already found the intensity at the point of interest, so we can calculate the intensity in decibels at this point with equation 1

    β = 10 log(2.0 10⁻⁶ / 1.0 10⁻¹²)

    β = 10 log ( 2 10⁶) = 10  6.3

    β = 63 dB

The intensity level in the room is 63 dB

5 0
3 years ago
The two particles are both moving to the right. Particle 1 catches up with particle 2 and collides with it. The particles stick
Irina18 [472]

Answer:

See bolded below.

Explanation:

Consider the " Before " and " After. " " Before, " this particle 1 was trying to catch up with this particle 2, and " after " particle one had collided with particle two. Take a look at the attachment below for a more detailed examination.

Here is how this will play out. Particle 1, with great velocity, will hit particle 2, which would mean that Particle 2 has less velocity than Particle 1. Now after the collision, energy is transferred to Particle 2, and while Particle 1 has now stopped in it's tracks, Particle 2 - with more energy than before - will continue as long as it has to before friction eventually brings it to a stop.

_______________________________________________________

From this we can conclude that Vf, from the picture below, must have less energy than V1, but more energy than V2 - and vice versa.

8 0
3 years ago
Roger drives his car at a constant speed of 80 km/hr. How far can he travel in 2 hrs. and 30 minutes?
bonufazy [111]

Answer:

200 km/hr

Explanation:

Since he goes 80km per hour, multiply this by 2.5 or two and a half hours.

80 x 2.5 = 200 km/hr.

6 0
2 years ago
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