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melisa1 [442]
2 years ago
5

How many protons, electrons, and neutrons are present in an atom of cr-24?

Physics
1 answer:
mote1985 [20]2 years ago
8 0

The number of protons, electrons, and neutrons in the atom of cr-24 is 28, 24, and 24 respectively.

<h3>What is atom?</h3>

An atom is the smallest unit of matter, consisting of the positively charged nucleus and the electrons which move around it. The atom can not be divided further.

The atom of a matter is made by three elements-

  • 1) Neutron-Neutron is the element of an atom, which has zero charge.
  • 2) Proton-Proton is the element of an atom, which has a positive charge.
  • 3) Electron-Electron is the element of an atom, which has a negative charge.

The atom of cr-24 has the atomic number 24. The atomic number of atom is equal to the number of proton and electron in an atom. Thus,

\rm Proton=24\\\rm Electron=24

Now, if this atom has the mass number of 52 (most common). Then the number of neutron is,

\rm Neutrons=Mass\; Number-Atomic\; Number\\\rm Neutrons=52-24\\\rm Neutrons=28

Thus, the number of protons, electrons, and neutrons in the atom of cr-24 is 28, 24, and 24 respectively.

Learn more about the atom here;

brainly.com/question/17545314

#SPJ4

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max2010maxim [7]

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3 0
3 years ago
Cuanto es tres por dos más cinco<br>3 * 2 + 5 es igual ​
Simora [160]

Answer:

3×2+5=11

Explanation:

3×2+5=

6+5

11

4 0
3 years ago
Gladiators of Physics Plz Help On This Question. Steps will help! with formula
arsen [322]
Simplified gravitational potential energy:
v = mgh

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g gravitational acceleration, on earth = 9.81m/s²
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8 0
3 years ago
A Chevrolet Corvette convertible can brake to a stop from a speed of 60.0 mi/h in a distance of 123 ft on a level roadway. What
Digiron [165]

Answer:

83.1946504051 m

Explanation:

u = Initial velocity = 60\ mph=\dfrac{60\times 1609.34}{3600}=26.82233\ m/s

s = Displacement = 123\ ft=\dfrac{123}{3.281}=37.4885705578\ m

\theta = Angle = 26^{\circ}

v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{0^2-26.82233^2}{2\times 37.4885705578}\\\Rightarrow a=-9.5954230306\ m/s^2

Coefficient of friction

\mu=-\dfrac{a}{g}\\\Rightarrow \mu=\dfrac{9.5954230306}{9.81}\\\Rightarrow \mu=0.978126710561

mg sin\theta - u mg cos\theta = ma\\\Rightarrow a=9.81(sin26-0.978126710561cos26)\\\Rightarrow a=-4.32382\ m/s^2

v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-26.82233^2}{2\times -4.32382}\\\Rightarrow s=83.1946504051\ m

The stopping distance is 83.1946504051 m

6 0
4 years ago
Which of the following require friction?
Bess [88]

Explanation:

Option D all of the above

if this helps you then please make me brainlist

7 0
2 years ago
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