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aksik [14]
4 years ago
11

A silver atom is converted to a silver ion when the atom

Chemistry
1 answer:
Anastaziya [24]4 years ago
5 0
Loses 1 atom. in this case, the silver atom achieves a <span>pseudo-noble-gas electron configuration.</span>
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If an ion has 22 protons and 18 electrons, then what is its charge?
son4ous [18]
It has a positive charge, 22-18= +4
3 0
4 years ago
Read 2 more answers
2.54 mL of ethanol to mol ethanol (Hint: the density of ethanol is 0.789<br> g/mL.)
Katarina [22]

0.04350179862

Explanation:

Make sure to check for sig figs though. Basically, you have 2.54 mL and you multiply that by the 0.789 g/mL and mL cancels out and you are left with 2.00406g. There are 46.06844 grams per mol of ethanol, so to cancel out grams we multiply by 1/46.06844. And then we are left with 0.04350179862 mol

7 0
4 years ago
I need help ASAP 10 points
jekas [21]

Answer:

the sun beams down on the pool and heats it up top to bottom the deeper the colder

4 0
3 years ago
Consider the reaction. PCl5(g)↽−−⇀PCl3(g)+Cl2(g) K=0.042 The concentrations of the products at equilibrium are [PCl3]=0.18 M and
tatyana61 [14]

<u>Answer:</u> The equilibrium concentration of PCl_5 is 1.285 M.

<u>Explanation:</u>

The chemical equation for the decomposition of phosphorus pentachloride follows:

PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)

The expression for equilibrium constant is given as:

K_c=\frac{[PCl_3][Cl_2]}{[PCl_5]}

We are given:

K_c=0.042

[PCl_3]=0.18M

[Cl_2]=0.30M

The concentration of solid substances are taken to be 1. Thus, they do not appear in the equilibrium constant expression.

Putting values in above equation, we get:

0.042=\frac{0.18\times 0.30}{[PCl_5]}

[PCl_5]=1.285

Hence, the equilibrium concentration of PCl_5 is 1.285 M.

6 0
3 years ago
Determine the type of reaction for the following equation:<br> C2H6 + O2à H2O + CO2
valkas [14]

Answer:

The type of reaction for the following equation is combustion equation.

Explanation:

Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.

\text{hydrocarbon}+O_2\rightarrow CO_2+H_2O

The reaction given to us:

C_2H_6 + \frac{7}{2}O_2\rightarrow 3H_2O + 2CO_2

When 1 mole of ethane reacts with 7/2 moles of oxygen gas it gives 3 moles of water and 2 moles of carbon dioxide gas.

The type of reaction for the following equation is combustion equation.

4 0
3 years ago
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