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Alexxx [7]
3 years ago
14

Which set of coefficients will balance the equation below? NaOH + Cu(NO3)2 Cu(OH)2 + NaNO3

Chemistry
2 answers:
Nonamiya [84]3 years ago
6 0
Answer is D
2 NaOH + 1Cu(NO3)2<span>  equals  1Cu(OH)2 + 2NaNO3

</span>
FinnZ [79.3K]3 years ago
5 0
The answer is D 2,1,1,2

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What is the new volume of a balloon originally at 755 torr and 5.00 l is placed in a container in which the pressure is increase
Luba_88 [7]

Answer is: volume will be 3.97 liters.

Boyle's Law: the pressure volume law -  volume of a given amount of gas held  varies inversely with the applied pressure when the temperature and mass are constant.

p₁V₁ = p₂V₂.

p₁ = 755 torr.

V₁ = 5.00 l.

p₂ = 1.25 atm · 760 torr/atm.

p₂ = 950 torr.

755 torr · 5 l = 950 torr · V₂.

V₂ = 755 torr · 5 l / 950 torr.

V₂ =  3.97 l.

When pressure goes up, volume goes down.

When volume goes up, pressure goes down.

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3 years ago
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The reaction described in Part A required 3.40 L of sodium chloride. What is the concentration of this sodium chloride solution
Mumz [18]

Answer:

Part A:

First, convert molarity to moles by multiplying by the volume:

0.293 M AgNO3 = (0.293 moles AgNO3)/1 L x 1.19 L = 0.349 moles AgNO3

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2 years ago
Consider the reaction
Elena-2011 [213]
Value of Kc is E= 2.5
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3 years ago
I am the system that helps to give your body structure. I have joints that link up and cartilage so smooth. It absorbs lots of i
stepan [7]

Answer:

Skeletal system

Explanation:

The skeletal system is made up of all the bones, cartilage, and ligaments in the body. There are over 200 bones in the human skeleton, connected by joints which allow them to bend and rotate.

It protects the vital organs, gives our body form and structure, and allows us to move (or bust a move!)

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3 years ago
An industrial chemist studying bleaching and sterilizing prepares several hypoclorite buffers.
Vanyuwa [196]

Answer:

pH is 7.60

Explanation:

Let's think the equations:

HClO + H₂O  ⇄  ClO⁻  +  H₃O⁺

As every weak acid, we make an equilbrium

The salt is dissociated in solution

NaClO → Na⁺  +  ClO⁻

                  HClO    +    H₂O    ⇄    ClO⁻    +     H₃O⁺

Initially       0.3m                            0.35m

We have the moles of acid, and the moles of conjugate base.

Reacts          x                                    X                  X

Some amount has reacted, so I obtained (in equilibrium) the moles of base + that amount, and the same amount for H₃O⁺ (ratio is 1:1)

HClO    +    H₂O    ⇄    ClO⁻    +     H₃O⁺

0.3 - x                        0.35 + x           x

Let's make the expression for Ka

Ka = [ClO⁻] . [H₃O⁺]  /  [HClO]

(we don't add water, because it is included in Ka)

2.9x10⁻⁸ = (0.35+x).x  / (0.3-x)

Ka is in order of 10⁻⁸, I can assume that 0.3-x is 0.3  and 0.35 +x =0.3

2.9x10⁻⁸ = (0.35)x  / (0.3)

(2.9x10⁻⁸ .  0.3) /0.35 = x

2.48x10⁻⁸ = x

This is [H₃O⁺]

For pH = - log [H₃O⁺]

pH = 7.60

3 0
3 years ago
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