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oksian1 [2.3K]
3 years ago
13

You make an observation that two objects attract. Which object below indicates the claim(s) that could be supported by this obse

rvation?
1.Both objects have a net charge.

2.Neither of the objects have a net charge.

3.One object has a net charge and the other object is neutral.

4.All of the above.

5.and C.
Physics
1 answer:
wel3 years ago
4 0
4. All of the above.





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Match the particles with their characteristics,
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Positive charge=proton
Negative charge=electron
No charge/neutral=neutron
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3 years ago
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You are an engineer in charge of designing a new generation of elevators for a prospective upgrade to the Empire State Building.
katen-ka-za [31]

Answer:

22.505 seconds

Explanation:

V =19.8m/s

V = a*to

t1 = 19.8/3.3

= 6seconds

Distance travelled during acceleration

= 1/2 x 3.3 x 6²

= 59.4m

X_total = x1 + x2

X2 = 373-59.4

X2 = 313.6m

t2 = x2/v

= 313.6/19.8

= 16.505

Total = 16.505 + 6

= 22.505 seconds

the minimum time in which an elevator can travel the 373 m from the ground floor is 22.505 seconds.

7 0
3 years ago
The diagrams show objects’ gravitational pull toward each other. Which statement describes the relationship between diagram X an
creativ13 [48]

' C ' is the only correct statement on the list.  We don't know anything about diagram-x or diagram-y because we can't see them.

8 0
3 years ago
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a hammer drops from a height of 8 meters. calculate the speed with which it hits the ground. show work
ioda

Answer:

12.5 m/s

Explanation:

The motion of the hammer is a free fall motion, so a uniformly accelerated motion, therefore we can use the following suvat equation:

v^2-u^2=2as

Where, taking downward as positive direction, we have:

s = 8 m is the displacement of the hammer

u = 0 is the initial velocity (it is dropped from rest)

v is the final velocity

a=g=9.8 m/s^2 is the acceleration of gravity

Solving the equation for v, we find the final velocity:

v=\sqrt{u^2+2as}=\sqrt{0+2(9.8)(8)}=12.5 m/s

So, the final speed is 12.5 m/s.

3 0
3 years ago
A box of mass 26 kg is initially at rest on a flat floor. The coefficient of kinetic friction between the box and the floor is 0
Kazeer [188]

Answer:

\Delta K = 52J

Explanation:

The change in kinetic energy will be simply the difference between the final and initial kinetic energies: \Delta K=K_f-K_i

We know that the formula for the kinetic energy for an object is:

K=\frac{mv^2}{2}

where <em>m </em>is the mass of the object and <em>v</em> its velocity.

For our case then we have:

\Delta K = K_f-K_i=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}=\frac{m(v_f^2-v_i^2)}{2}

Which for our values is:

\Delta K = \frac{m(v_f^2-v_i^2)}{2} = \frac{(26Kg)((2m/s)^2-(0m/s)^2)}{2} = 52J

3 0
3 years ago
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