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jolli1 [7]
3 years ago
6

A skier starting from rest skis straight down a slope 50 meters long in 5.0 seconds. What is the magnitude of the acceleration.

Physics
1 answer:
3241004551 [841]3 years ago
6 0
His average speed all the way is

                   (50 meters) / (5 sec)  =  10 m/s .

But, if the acceleration is uniform all the way down, then

            Average speed  =  (1/2) (start speed + end speed)

Start speed  =  0.
So
             Average speed  =  (1/2) (0 + end speed)

                                     =  (1/2) of end speed .

                   10 m/s        = (1/2) of end speed

               End speed (at the bottom)  =  20 m/s .

Magnitude of acceleration = (change in speed) / (time for the change)

                                      =     (20 m/s)            /    (5 sec)

                                       =                4 m/s²  .
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A sound wave has a frequency of 425 hz. what is the period of this wave? 0.00235 seconds 0.807 seconds 425 seconds 850 seconds
77julia77 [94]

The period of the sound wave at the given frequency is determined as 0.00235 second.

<h3>Period of the sound wave</h3>

The period of the sound wave at the given frequency is calculated as follows;

Period is reciprocal of frequency.

T = 1/f

T = 1/425

T = 0.00235 second

Thus, the period of the sound wave at the given frequency is determined as 0.00235 second.

Learn more about period here: brainly.com/question/10428039

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1 year ago
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3 years ago
A car traveling at 60 mph has how much more energy than a car going at 15 mph?
Liono4ka [1.6K]

4. KE increases by a factor of 16 is the answer

<u>Explanation:</u>

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where  

m  = mass, and  v = velocity.

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Answer:

D) The rubber object will become negatively charged, and the glass object will become positively charged.

Explanation:

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When we compare rubber and glass then we know that electron affinity of rubber is more as compare to glass.

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so correct answer will be

D) The rubber object will become negatively charged, and the glass object will become positively charged.

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