The number of kilowatts used by an individual to operate his appliances is determined as 12.1 kWh.
<h3>
Average daily power consumption</h3>
The average daily power consumption is the amount of electric energy consumed by an individual on a daily rate.
The average daily power consumption of individuals in USA is 12,100 W-hr.
<h3>Converting watts to kilowatts</h3>
E = 12,100 Whr/1000
E = 12.1 kWh
Thus, the number of kilowatts used by an individual to operate his appliances is determined as 12.1 kWh.
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It gets attracted due to electro magnetizing
Answer:
Explanation:
Its not a good practice to write all the functions including main() in the same class.
But as you opted for this, the code goes here like this:
public class CalcPyramidVolume {
/* Your solution goes here */
static double pyramidVolume(double baseLength, double baseWidth, double pyramidHeight)
{
double Volume,baseArea;
baseArea = baseLength * baseWidth;
Volume = baseArea * pyramidHeight * 1/3;
return Volume;
}
public static void main (String [] args) {
System.out.println("Volume for 1.0, 1.0, 1.0 is: " + pyramidVolume(1.0, 1.0, 1.0));
return;
}
}
And there is not caveat of integer division, as you are declaring all your variables of type double.
Considering the four electric charges forming a square with magnitude of charge of 2.0 nC on each. :
A) Magnitude of the force on the 5.5 nC charge in the middle of the figure = 3.48 * 10^-4 N
B) Direction of the force on the 5.5 nC charge in the middle of the figure = Leftward ( negative x -axis )
Using the given data :
size of square = 4 cm
magnitudes of four charges = 2.0 nC
<u> a) </u><u>magnitude</u><u> of the force on the center charge </u>
Electric force between two point charges = 
----- ( 1 )
where ; 
step 1 ; find r ( distance between charges )
r² = ( 2 )² + ( 2 )² = 8 cm²
back to equation 1
F = 9 * 10⁹ * 
= 1.23 * 10^-4 N
∴ magnitude of the force on the center charge ( Fnet )= 4F cos 45°
= 4 * ( 1.23 * 10^-4 ) * 
= 3.48 * 10^-4 N
b) The direction of the force at the center is along the negative x-axis ( leftward )
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