Answer: -
Thus the resulting atomic number of an element that emits 1 alpha particle, 1 positron, and 3 beta particles is the same as original.
Explanation: -
Let the mass number be A and the atomic number be Z.
When an alpha particle is emitted, the mass number decreases by 4 and the atomic number decreases by 2.
Thus after alpha particle the new mass number = A - 4
Thus after alpha particle the new atomic number = Z - 2
When a positron is emitted, the atomic number only decreases by 1.
Thus after positron emission the new mass number = A - 4
Thus after positron emission the new atomic number = Z - 2 - 1
= Z - 3
When a beta particle is emitted, the atomic number increases by 1.
For 3 beta particles, the atomic number will increase by 3.
Thus after beta particle emission the new mass number = A - 4
Thus after beta particle emission the new atomic number = Z - 3+3
= Z
Thus the resulting atomic number of an element that emits 1 alpha particle, 1 positron, and 3 beta particles is the same as original.
