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Fynjy0 [20]
3 years ago
7

The resulting atomic number of an element that emits 1 alpha particle, 1 positron, and 3 beta particles is

Chemistry
1 answer:
Natalka [10]3 years ago
4 0

Answer: -

Thus the resulting atomic number of an element that emits 1 alpha particle, 1 positron, and 3 beta particles is the same as original.

Explanation: -

Let the mass number be A and the atomic number be Z.

When an alpha particle is emitted, the mass number decreases by 4 and the atomic number decreases by 2.

Thus after alpha particle the new mass number = A - 4

Thus after alpha particle the new atomic number = Z - 2

When a positron is emitted, the atomic number only decreases by 1.

Thus after positron emission the new mass number = A - 4

Thus after positron emission the new atomic number = Z - 2 - 1

= Z - 3

When a beta particle is emitted, the atomic number increases by 1.

For 3 beta particles, the atomic number will increase by 3.

Thus after beta particle emission the new mass number = A - 4

Thus after beta particle emission the new atomic number = Z - 3+3

= Z

Thus the resulting atomic number of an element that emits 1 alpha particle, 1 positron, and 3 beta particles is the same as original.

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What is the difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm
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Answer:

The difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm is :

<u>Difference</u>  <u>in mass</u> =<u> 985.32 - 984.5 = 0.82 g</u>

Explanation:

<u>Part I :</u>

n =\frac{3.01\times 10^{24}}{6.022\times 10^{23}}

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n = 4.99 moles

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<u>Part II :</u>

Density of Gold = 19.32 g/cm^{3}

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Volume of the gold bar =6.00\times 4.25\times 2.00

Volume of the gold bar = 51cm^{3}

Using formula,

Density = \frac{mass}{Volume}

Mass = Density\times Volume

Mass = 19.32 \times 51

Mass = 985.32 g

So, A  gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm has mass of <u>985.32 g</u>

<u>Difference</u>  <u>in mass</u> =<u> 985.32 - 984.5 = 0.82 g</u>

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