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galina1969 [7]
3 years ago
10

To analyze the motion of a body that is traveling along a curved path, to determine the body's acceleration, velocity, and posit

ion. A motorcyclist travels around a curved path that has a radius of 250 ft . While traveling around the curved path, the motorcyclist increases speed by 1.05 ft/s2 . Part A - Finding the time interval for the motorcyclist to reach a given acceleration If the motorcyclist starts from rest, determine the time needed to reach an acceleration of 4.25ft/s2. Express your answer to three significant figures and include the appropriate units.
Physics
1 answer:
Brilliant_brown [7]3 years ago
6 0

Answer:

a^2 = ar^2 + al^2      where ar is the radial acceleration and al is the

linear acceleration - since vectors ar and al are at right angles

ar^2 = a^2 - al^2 = 4.25^2 - 1.05^2

ar = 4.12 ft/s^2

ar = V^2 / R     where ar is the radial acceleration

So V^2 = ar * R = 4.12 * 250 = 1030 ft^2/s^2

V = 32.1 m/s    the linear speed of the cycle

Also, V = al t   or t = V / al = 32.1 / 1.05 = 30.6 sec

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Answer:

0.15625 grams

Explanation:

Half life: It is related to the decay of radioactive material. The duration in which  half of the material will be degraded/decayed. That means after half life 50% of the radioactive material will be left. Here the half life is 28 years.

Initial quantity of the sample: 2.5 grams.

After 28 years, the leftover quantity = 1.25 grams

After 56 years, the leftover quantity = 0.625 grams

After 84 Years, the leftover quantity = 0.3125 grams

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8 0
3 years ago
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tyhe mass of an object is 117 g adding 1200j of heat will raise the temperture of the object by 12 celsius what is the specifc h
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Answer:

C 0.85 j/g*k

Explanation:

The specific heat capacity of a material is given by:

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Q is the amount of heat supplied to the object

m is the mass of the object

\Delta T is the increase in temperature of the object

For the object in this problem, we have

m = 117 g is the mass

Q = 1200 J is the heat supplied

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Substituting into the formula, we find the specific heat:

C_s = \frac{1200 J}{(117 g)(12^{\circ})}=0.85 J/gC

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3 years ago
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const2013 [10]

Answer:

1.62 atm

Explanation:

We can solve the problem by using the ideal gas equation:

pV=nRT

where:

p = ? is the pressure of the gas in the tire

V = 8.5 L is the volume of the tire

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By re-arranging the equation and substituting the numbers in, we find:

p=\frac{nRT}{V}=\frac{(0.55 mol)(0.0821 Latm/Kmol)(305 K)}{8.5 L}=1.62 atm

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3 years ago
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