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dangina [55]
3 years ago
10

4. According to Reference Table G, how many grams of KNO3 would be needed to saturate 200 grams of

Chemistry
1 answer:
e-lub [12.9K]3 years ago
6 0

Answer:

The answer is choice (4) 268 g.

Explanation:

To find this answer you have to go to the reference table, using Table G, and go to KNO3 at 70°C. Find out how many grams saturate potassium nitrate (134 g). Then you double it (268 g ) because it's asking for grams at 200 grams of water.

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Calculate the number of moles of an ideal gas if it occupies 1750 dm3 under 125,000 pa at a temperature of 127 c. a. 0.21 moles
labwork [276]

The number of mole will be 65.81 mole.

An ideal gas would be one for which both the overall volume of the molecules and even the forces that exist between them are so negligible as to have no influence on the behavior of something like the gas.

Number of ideal gas can be calculated by using the formula:

PV = nRT

where, p is pressure, n is number of mole, R is gas constant and T is temperature.

Given data:

V= 1750 dm^{3} = 1750 L

P = 125,000 p = 1.2 atm

R = 0.082 L /mole kelvin

T = 273+127 = 400 K

Now, put the value of given data in above equation.

1.23atm x 1750L = n x 0.0820atm x Liter/ mole x kelvin  x 400K

n = 65.81 mole.

Therefore, the number of mole will be 65.81 mole

To know more about mole

brainly.com/question/21050624

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6 0
2 years ago
Which of these elements has a smaller atomic #? 1=aluminum 2=beryllium 3=tungsten
enot [183]
2
refer to periodic table for explanation
6 0
3 years ago
How does the mass number of an element differ from its average atomic mass?
Aleonysh [2.5K]
The mass number is the total number of protons and neutrons in a nucleus of an element. The average atomic mass is the sum of the masses of an element's isotopes, each multiplied by their abundance.
4 0
3 years ago
Determine the concentrations of K2SO4, K , and SO42– in a solution prepared by dissolving 1.80 × 10–4 g K2SO4 in 1.50 L of water
Cloud [144]
We are given with
<span>1.80 × 10–4 g K2SO4
</span><span>1.50 L of water

The concentration of K2SO4 is
</span>1.80 × 10–4 g K2SO4 x (1 mole K2SO4 / 174 g K2SO4) x (1 / 1.50 L)
= 6.897 x 10-7 M

Since K2SO4 dissociates into
K2SO4 <=> 2K+  +  SO4-2

The concentration of K+ ions is
2 x 6.897 x 10-7 M = 1.379 x 10-6 M

The concentration of SO4-2 is the same as that of K2SO4
1.379 x 10-6 M
8 0
3 years ago
Read 2 more answers
A solution is made by dissolving
ipn [44]

Answer:

2.21m

Explanation:

Molality, m, is defined as the ratio between moles of solute (The substance that is in less amount, sodium sulfide) and kilograms of solvent (Water, in this case).

Thus, we need to convert mass of sodium sulfide to moles using its molar mass and grams of water to kilograms:

<em>Moles Na2S (Molar mass: 78.0452g/mol):</em>

37.5g * (1mol / 78.0452g) = 0.48 moles Na2S

<em>Kilograms water:</em>

217g * (1kg / 1000g) = 0.217kg

Molality:

0.48 moles Na2S / 0.217kg =

<h3>2.21m</h3>
7 0
3 years ago
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