Answer:
Filtration
Explanation:
Filtration is used to separate solid substances from liquids or large molecules from small molecules. Since, Acid is a liquid and metal oxide is solid so Filtration can be used to separate these two.
Answer:
![\Delta _RH=4x10^{-3}\frac{kJ}{mol}](https://tex.z-dn.net/?f=%5CDelta%20_RH%3D4x10%5E%7B-3%7D%5Cfrac%7BkJ%7D%7Bmol%7D)
Explanation:
Hello,
In this case, the molar enthalpy of reaction is obtained by dividing the involved energy by the reacting moles:
![\Delta _RH=\frac{12J}{3mol} =4\frac{J}{mol}](https://tex.z-dn.net/?f=%5CDelta%20_RH%3D%5Cfrac%7B12J%7D%7B3mol%7D%20%3D4%5Cfrac%7BJ%7D%7Bmol%7D)
Thus, it is important to notice that the compound "uses" the energy, it means that it absorbs the energy, for that reason the sign is positive. Moreover, computing the result in kJ/mol we finally obtain:
![\Delta _RH=4\frac{J}{mol}*\frac{1kJ}{1000J} =4x10^{-3}\frac{kJ}{mol}](https://tex.z-dn.net/?f=%5CDelta%20_RH%3D4%5Cfrac%7BJ%7D%7Bmol%7D%2A%5Cfrac%7B1kJ%7D%7B1000J%7D%20%3D4x10%5E%7B-3%7D%5Cfrac%7BkJ%7D%7Bmol%7D)
Best regards.
Answer:
VH2SO4 = 145.3 mL
Explanation:
Mw BaO2 = 169.33 g/mol
⇒ mol BaO2 = 53.5g * ( mol BaO2 / 169.33 g BaO2) = 0.545 mol BaO2
⇒according to the reaction:
mol BaO2 = mol H2SO4 = 0.545 mol
⇒ V H2SO4 = 0.545 mol H2SO4 * ( L H2SO4 / 3.75 mol H2SO4 )
⇒V H2SO4 = 0.1453 L (145.3 mL)
A.)49.4974874 moles or 49.5 moles
B.)2.980808730172671e+25 or 3e+25
Answer:
The gecko's feet have tiny suction cups on them that stick to the surface.