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3 years ago

Which is a characteristic of projectile motion?

Physics

2 answers:

professor190 [17]3 years ago

8 0

Answer:

Explanation:

The projectile motion is an example of two dimensions motion. It is a motion in two dimensions under the force of gravity.

When a projectile throws at any arbitrary angle other than 0 degree or 90 degree, it covers both horizontal and vertical distance.

The horizontal distance is called height and horizontal distance is called range.

The formula for the vertical height is given by

$H = \frac{u^{2}Sin^{2}\theta }{2g}$

The formula for the horizontal range is given by

$R = \frac{u^{2}Sin 2\theta }{g}$

Ne4ueva [31]3 years ago

3 0

A projectile<span> is an object upon which the only force acting is gravity. Many </span>projectiles<span> not only undergo a vertical </span>motion<span>, but also undergo a horizontal </span>motion<span>. That is, as they move upward or downward they are also moving horizontally.</span>

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Can someone help me?!!!!!

german

<h2>Hello!</h2>

The answer is:

The first option, the walker traveled 360m more than the actual distance between the start and the end points.

Why?

Since each block is 180 m long, we need to calculate the vertical and the horizontal distance, in order to calculate how farther did the travel walk between the start and the end points (displacement).

So, calculating we have:

Traveler:

$Distance=NorthCoveredDistance+EastCoveredDistance$

$Distance=4*180m+3*180m=720m+540m=1260m$

Actual distance between the start and the end point (displacement):

$ActualDistance=\sqrt{NorthDistance+EastDistance}\\\\ActualDistance=\sqrt{NorthDistance^{2} +EastDistance^{2}}\\\\ActualDistance=\sqrt{(720m)^{2} +(540m)^{2}}\\\\ActualDistance=\sqrt{518400m^{2} +291600m^{2}}\\\\ActualDistance=\sqrt{810000m^{2}}=900m$

Now, to calculate how much farter did the traveler walk, we need to use the following equation:

$DistanceDifference=WalkerCoveredDistance-ActualDistance\\\\DistanceDifference=1260m-900m=360m$

Therefore, we have that distance differnce between the distance covered by the walker and the actual distance is 360m.

Hence, we have that the walker traveled 360m more than the actual distance between the start point and the end point.

Have a nice day!

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Ymorist [56]

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