Which scenario would result in the fastest rate of dissolution?

What does the number at the top of the square above tell you about carbon?

Alona [7]

Answer:

A carbon nucleus has 6 protons.

Explanation:

The Atomic number tells u how many protons are in the nucleus of an atom

Hope this helps!

8 0

3 years ago

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A 0.250 kgkg toy is undergoing SHM on the end of a horizontal spring with force constant 300 N/mN/m. When the toy is 0.0120 mm f

konstantin123 [22]

Answer:

(a) The total energy of the object at any point in its motion is 0.0416 J

(b) The amplitude of the motion is 0.0167 m

(c) The maximum speed attained by the object during its motion is 0.577 m/s

Explanation:

Given;

mass of the toy, m = 0.25 kg

force constant of the spring, k = 300 N/m

displacement of the toy, x = 0.012 m

speed of the toy, v = 0.4 m/s

(a) The total energy of the object at any point in its motion

E = ¹/₂mv² + ¹/₂kx²

E = ¹/₂ (0.25)(0.4)² + ¹/₂ (300)(0.012)²

E = 0.0416 J

(b) the amplitude of the motion

E = ¹/₂KA²

$A = \sqrt{\frac{2E}{K} } \\\\A = \sqrt{\frac{2*0.0416}{300} } \\\\A = 0.0167 \ m$

(c) the maximum speed attained by the object during its motion

$E = \frac{1}{2} mv_{max}^2\\\\v_{max} = \sqrt{\frac{2E}{m} } \\\\v_{max} = \sqrt{\frac{2*0.0416}{0.25} } \\\\v_{max} = 0.577 \ m/s$

8 0

3 years ago

An electron with a speed of 1.9 × 107 m/s moves horizontally into a region where a constant vertical force of 4.9 × 10-16 N acts

Nimfa-mama [501]

Explanation:

It is given that,

Speed of the electron in horizontal region, $v=1.9\times 10^7\ m/s$

Vertical force, $F_y=4.9\times 10^{-16}\ N$

Vertical acceleration, $a_y=\dfrac{F_y}{m}$

$a_y=\dfrac{4.9\times 10^{-16}\ N}{9.11\times 10^{-31}\ kg}$

$a_y=5.37\times 10^{14}\ m/s^2$ ..........(1)

Let t is the time taken by the electron, such that,

$t=\dfrac{x}{v_x}$

$t=\dfrac{0.024\ m}{1.9\times 10^7\ m/s}$

$t=1.26\times 10^{-9}\ s$ ...........(2)

Let $d_y$ is the vertical distance deflected during this time. It can be calculated using second equation of motion:

$d_y=ut+\dfrac{1}{2}a_yt^2$

u = 0

$d_y=\dfrac{1}{2}\times 5.37\times 10^{14}\ m/s^2\times (1.26\times 10^{-9}\ s)^2$

$d_y=0.000426\ m$

$d_y=0.426\ mm$

So, the vertical distance the electron is deflected during the time is 0.426 mm. Hence, this is the required solution.

3 0

3 years ago

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What is the meaning of agility

tamaranim1 [39]

Answer:

Agility or nimbleness is an ability to change the body's position efficiently, and requires the integration of isolated movement skills using a combination of balance, coordination, speed, reflexes, strength and endurance.

Explanation:

Hope this helps I don't know if this is what you were looking for?

8 0

3 years ago

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An object at rest has no net force acting on it.<br><br> True<br> False

aivan3 [116]

Yes that's true according to newton's first law

5 0

4 years ago

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