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Vanyuwa [196]
3 years ago
10

Bela made scrambled eggs while camping. She placed the eggs in a pan on the grill, then turned on the flame to apply heat to the

pan and the eggs. By applying heat, Bela increased the _______________ of the eggs. She could measure how much the_______________increased with a thermometer.
Chemistry
2 answers:
Alina [70]3 years ago
7 0

Answer: Temperature.

stira [4]3 years ago
7 0

Explanation:

Thermal energy is defined as the internal energy of an object because of the kinetic energy present within the molecules of the object.

As relation between kinetic energy and temperature is as follows.

        K.E = \frac{3}{2}kT

So, with increase in temperature there will also occur an increase in kinetic energy which leads to an increase in thermal energy of the substance.

Therefore, we can conclude that by applying heat, Bela increased the thermal energy of the eggs. She could measure how much the temperature increased with a thermometer.

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Hydrogen is 99% hydrogen-1; 0.8% hydrogen-2; and 0.2% hydrogen-3. calculate it's average atomic mass
alexandr402 [8]
Average atomic mass is =1.11 u

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4 0
3 years ago
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Calculate the value of [CH3OH][CO][H2]2 when all concentrations are 2.4. Keep in mind that the reaction may not be at equilibriu
NikAS [45]

Explanation:

The given reaction will be as follows.

            CO + 2H_{2} \leftrightharpoons CH_{3}OH

So, equilibrium constant for this equation will be as follows.

              K_{c} = \frac{[CH_{3}OH]}{[CO][H_{2}]^{2}}

As it is given that concentration of all the species is 2.4. Therefore, calculate the value of equilibrium constant as follows.

               K_{c} = \frac{[CH_{3}OH]}{[CO][H_{2}]^{2}}

                       = \frac{2.4}{2.4 \times (2.4)^{2}}

                       = 0.173

Thus, we can conclude that equilibrium constant for the given reaction is 0.173.  

3 0
3 years ago
2. The Food and Drug Administration (FDA) mandates that all vinegar sold in the United States must have a minimum concentration
Scilla [17]

Answer:

The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.

Explanation:

4% acetic acid by mass means that 4 gram of acetic acid in 100 g solution.

Given that density of the vinegar is same is that of water =  1 g/mL

Mass of the vinegar solution = 100 g

Volume of the vinegar solution = V

Density=\frac{Mass}{Volume}

1 g/mL=\frac{100 g}{V}

V = 100 mL = 0.1 L

Moles of acetic acid =\frac{4 g}{60.052 g/mol}=0.0666 mol

Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution(L)}}

M=\frac{0.0666 mol}{0.1 L}=0.6660 mol/L

The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.

4 0
4 years ago
I need help plz this is driving me crazy
Elis [28]
A= 6 
B= 2
C= 1
D= 5
E= 3
F= 4
4 0
3 years ago
What is the standard electrode potential for a galvanic cell constructed in the appropriate way from these two half-cells?
____ [38]

E

θ

Cell

=

+

2.115

l

V

Cathode

Mg

2

+

/

Mg

Anode

Ni

2

+

/

Ni

Explanation:

Look up the reduction potential for each cell in question on a table of standard electrode potential like this one from Chemistry LibreTexts. [1]

Mg

2

+

(

a

q

)

+

2

l

e

−

→

Mg

(

s

)

−

E

θ

=

−

2.372

l

V

Ni

2

+

(

a

q

)

+

2

l

e

−

→

Ni

(

s

)

−

E

θ

=

−

0.257

l

V

The standard reduction potential

E

θ

resembles the electrode's strength as an oxidizing agent and equivalently its tendency to get reduced. The reduction potential of a Platinum-Hydrogen Electrode under standard conditions (

298

l

K

,

1.00

l

kPa

) is defined as

0

l

V

for reference. [2]

A cell with a high reduction potential indicates a strong oxidizing agent- vice versa for a cell with low reduction potentials.

Two half cells connected with an external circuit and a salt bridge make a galvanic cell; the half-cell with the higher

E

θ

and thus higher likelihood to be reduced will experience reduction and act as the cathode, whereas the half-cell with a lower

E

θ

will experience oxidation and act the anode.

E

θ

(

Ni

2

+

/

Ni

)

>

E

θ

(

Mg

2

+

/

Mg

)

Therefore in this galvanic cell, the

Ni

2

+

/

Ni

half-cell will experience reduction and act as the cathode and the

Mg

2

+

/

Mg

the anode.

The standard cell potential of a galvanic cell equals the standard reduction potential of the cathode minus that of the anode. That is:

E

θ

cell

=

E

θ

(

Cathode

)

−

E

θ

(

Anode

)

E

θ

cell

=

−

0.257

−

(

−

2.372

)

E

θ

cell

=

+

2.115

Indicating that connecting the two cells will generate a potential difference of

+

2.115

l

V

across the two cells.

5 0
2 years ago
Read 2 more answers
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