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3 years ago

15

describe a process in which energy changes forms at least twice. are there any unwanted forms of energy that are produced during

the energy transformations?

1 answer:

erma4kov [3.2K]3 years ago

6 0

Heating your food on a gas stove.

The thermal potential energy within the flammable gas is released due to the electric spark that is produced by a voltage or potential difference if automated. And if manual, a spark ignites the flame due to friction of abrasive metals releasing ionic bonds and creating a spark. The flame heats the underside of the pan and trasmit thermal energy to heat increasing temperature and therefore unlocking the potential energy of the food into thermal energy. and so on.

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A wave with a frequency of 80 Hz travels through rubber with a wavelength of 7.0 m. What is the velocity of the wave?

Scorpion4ik [409]

Answer:

560 m/s

Explanation:

Given,

Frequency ( f ) = 80 hz

Wavelength ( λ ) = 7.0 m = 7m

To find : Velocity ( v )

Formula : -

v = f λ

v = 80 x 7

v = 560 m/s

Hence, the velocity of the wave is 560 m/s.

5 0

2 years ago

A spring with spring constant 33N/m is attached to the ceiling, and a 4.8-cm-diameter, 1.5kg metal cylinder is attached to its l

mylen [45]

Answer:

0.423m

Explanation:

Conversion to metric unit

d = 4.8 cm = 0.048m

Let water density be $\who_w = 1000 kg/m^3$

Let gravitational acceleration g = 9.8 m/s2

Let x (m) be the length that the spring is stretched in equilibrium, x is also the length of the cylinder that is submerged in water since originally at a non-stretching position, the cylinder barely touches the water surface.

Now that the system is in equilibrium, the spring force and buoyancy force must equal to the gravity force of the cylinder. We have the following force equation:

$F_s + F_b = W$

Where $F_s = kx$ N is the spring force, $F_b = W_w = m_wg = \rho_w V_s g$ is the buoyancy force, which equals to the weight $W_w$ of the water displaced by the submerged portion of the cylinder, which is the product of water density $\rho_w$ , submerged volume $V_s$ and gravitational constant g. W = mg is the weight of the metal cylinder.

$kx + \rho_w V_s g = mg$

The submerged volume would be the product of cross-section area and the submerged length x

$V_s = Ax = \pi(d/2)^2x$

Plug that into our force equation and we have

$kx + \rho_w \pi(d/2)^2x g = mg$

$x(k + \rho_w g \pi d^2/4) = mg$

$x = \frac{m}{(k/g) + (\rho_w\pi d^2/4)} = \frac{1.5}{(33/9.8) + (100*\pi * 0.048^2/4)} = 0.423 m$

6 0

3 years ago

Can someone help me with these questions plz

Korolek [52]

Im not 100% on these but i can try

1. A compound is made up of elements and their different atoms

2.

A. salt- compound (NaCl) is two elements Na (sodium) and Cl (chloride?)

B. Nitrogen- element its on the periodic table

C. Helium- element its on the periodic table

D. Water- compound (H2O) two elements hydrogen and oxygen

3. element, compound, compound, element

Hope this helps

8 0

3 years ago

Proyektil dengan massa 10 gram ditembak dari senapan dengan massa 5 kg. Kecepatan proyektil sesaat setelah memotret dari laras a

notka56 [123]

Answer:

-0.4 m/s

Explanation:

According to the law of conservation of momentum, the total momentum of the bullet - rifle system must be conserved.

The total momentum before the shot is zero, since they are both at rest:

$p_i = 0$

While the total momentum after the shot can be written as:

$p_f = mv+MV$

where

m = 10 g = 0.010 kg is the mass of the bullet

M = 5 kg is the mass of the rifle

v = 200 m/s is the velocity of the bullet

V is the recoil velocity of the rifle

Since the total momentum is conserved, we can write:

$p_i = p_f$

So

$0=mv+MV$

And solving for V, we find the recoil velocity:

$V=-\frac{mv}{M}=-\frac{(0.010)(200)}{5}=-0.4 m/s$

and the negative sign indicates that the velocity is opposite to the bullet.

7 0

3 years ago

OleMash [197]

Answer:

R= 5.4 ohms

Explanation:

Given that

V= 9 V

Power ,P= 15 W

Lets take resistor resistance = R

We know that Power given as

$P=\dfrac{V^2}{R}$

V=Voltage

P=Power

R=Resistance

$R=\dfrac{V^2}{P}$

Now by putting the all the values in the above equation

$R=\dfrac{9^2}{15}$

R= 5.4 ohms

Therefore the resistance of the resister will be 5.4 ohms.

7 0

3 years ago