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mixer [17]
3 years ago
15

describe a process in which energy changes forms at least twice. are there any unwanted forms of energy that are produced during

the energy transformations?
Physics
1 answer:
erma4kov [3.2K]3 years ago
6 0
Heating your food on a gas stove.

The thermal potential energy within the flammable gas is released due to the electric spark that is produced by a voltage or potential difference if automated. And if manual, a spark ignites the flame due to friction of abrasive metals releasing ionic bonds and creating a spark. The flame heats the underside of the pan and trasmit thermal energy to heat increasing temperature and therefore unlocking the potential energy of the food into thermal energy. and so on.
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balandron [24]

Answer:

F=m*(v^2/r)

F=82*(8^2/30)

F=174.9N

Explanation:

brainlest pls

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Why can people float effortlessly on the dead sea?
ahrayia [7]
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An open pipe of length 0.39m vibrates in the third harmonic with a frequency of 1400Hz. What is the distance from the center of
Gnoma [55]

Length of the pipe = 0.39 m

Third harmonic frequency = 1400 Hz

For the third harmonic:

Wavelength = \frac{2L}{3}

The center of the open pipe will host a node and the nearest anti - node from the center will be at the 0.25 × wavelength

Distance from center  = 0.25 × wavelength

Distance = 0.25 x \frac{2L}{3}

Plugging the value of the length of the pipe (L) = 0.39 m = 39 cm

Distance = 0.25 x \frac{2 \times 39}{3}

Distance from the center to the nearest anti - node = 6.5 cm

Hence, the nearest distance to the anti - node from the center = 6.5 cm

So, option C is correct.

7 0
3 years ago
A gymnast dismounts off the uneven bars in a tuck position with a radius of 0.3m (assume she is a solid sphere) and an angular v
kifflom [539]

Here we will say that there is no external torque on the system so we will have

L_i = L_f

here we know that

L_i = I_1\omega_1

where we know that

I_1 = \frac{2}{5}mr^2

Also we know that

I_2 = \frac{1}{12}mL^2

initial angular speed will be

\omega_1 = 2\pi(2rev/s) = 4\pi rad/s

now from above equation

\frac{2}{5}mr^2 (4\pi) = \frac{1}{12}mL^2 \omega

0.4(0.3)^2(4\pi) = \frac{1}{12}(1.5)^2\omega

0.452 = 0.1875 \omega

now we have

\omega = 2.41 rad/s

so final speed will be 2.41 rad/s

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From an electromagnetic wave the electric and magnetic field is what direction toward each other?
liubo4ka [24]
What are the choices?
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3 years ago
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