Answer: Chilling with my homies
Chicken wings, Chicken wings
Hotdog and baloney
Chicken and macaroni
Chillin' wit mah homiiieees
Chicken wing chicken wing
Hot dogs and balogna
Chicken and macaroni
Chilling with mah Chilling with mah
Chicken chicken wing chicken chicken wing
Chicken chicken chicken chicken chicken wing
Chicken chicken chicken chicken wing
Chicken wings, Chicken wings
Hotdog and baloney
Chicken and macaroni
Chillin' wit mah homiiieees
Chicken wings, Chicken wings
Hotdog and baloney
Chicken and macaroni
Chillin' wit mah homiiieees homiiieeees
Chicken wings, Chicken wings
Hotdog and baloney
Chicken and macaroni
Chillin' wit mah homiiieees
Chillin' wit mah
Explanation:
im sorry i had to do it now pls give me brainliest thank u and have a blessed day:)
True, for electricity fossil fuels are burned to turn a steam turbine to generate electricity and natural gas is exactly what it says gas formed from the decay of plant and animal life long ago
Answer:
Period of oscillation = 1.33 seconds
Explanation:
The period of oscillation is given by:
T = 2π√[I/(MgL)]
for I = 2MR² and L = R,
Given: L = 0.22m = R
T = 2π√[2R/g]
T = 2 × 3.142 Sqrt[( 2 × 0.22)/ 9.8]
T = 6.284 Sqrt(0.44/9.8)
T = 6.284 Sqrt(0.0449)
T = 6.284 × 0.2119
T = 1.33 sec
Answer:
1) 10.1 s 2) 909 m 3) 90.0 m/s 4) -99m/s 5) just over the bomb.
Explanation:
1)
- In the vertical direction, as the bomb is dropped, its initial velocity is 0.
- So, we can find the time required for the bomb to reach the earth, applying the following kinematic equation for displacement:

- where Δy = -500 m (taking the upward direction as positive).
- a=-g=-9.8 m/s²
- Replacing these values in (1), and solving for t, we have:

- The time required for the bomb to reach the earth is 10.1 s.
2)
- In the horizontal direction, once released from the helicopter, no external influence acts on the bomb, so it will continue moving forward at the same speed. that it had, equal to the helicopter.
- As the time must be the same for both movements, we can find the horizontal displacement just as the product of this speed times the time, as follows:

3)
- The horizontal component of the bomb's velocity is the same that it had when left the helicopter. i.e. 90 m/s.
4)
- In order to find the vertical component of the bomb's velocity just before it strikes the earth, we can apply the definition of acceleration, remembering that v₀ = 0, as follows:

5)
- If the helicopter keeps flying horizontally at the same speed, it will be always over the bomb, as both travel horizontally at the same speed.
- So, when the bomb hits the ground, the helicopter will be exactly over it.