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ELEN [110]
3 years ago
13

In an experiment, mixing baking soda and vinegar produced a combination of salty water and carbon dioxide shown in the following

graph. What is the combined mass of the baking soda and vinegar before mixing?
45 grams
55 grams
35 grams
450 grams
Chemistry
2 answers:
Cloud [144]3 years ago
8 0

Answer:

Explanation:

answer

guajiro [1.7K]3 years ago
7 0
The answer is ..... obviously lol
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What is the volume of a 3.0 M solution of hydrochloric acid that contains 1.50 moles of solute?
charle [14.2K]
C - concentration: 3.0M
n - number of moles: 1.50 moles
V - volume: ???
____________
C = n/V
V = n/C
V = 1.5/3
V = 0,5 L = 500 mL

:)
4 0
3 years ago
How would you distinguish benzoic acid and benzyl alcohol by their infrared spectra?
Vadim26 [7]

The OH peaks in the IR spectra of benzyl alcohol and benzoic acid should be compared and contrasted.

<h3>What is the IR spectra of Benzoic acid?</h3>
  • The right-hand portion of the infrared spectrum of benzoic acid, between wavenumbers 1500 and 400 cm-1, is referred to as the fingerprint region.
  • It results from a special combination of intricately overlapping vibrations of the atoms within the benzoic acid molecule.
<h3>What is the IR spectra of Benzyl alcohol?</h3>
  • A C-Cl bond is frequently shown by a peak at 700.
  • There are a few more peaks at 1500 that are directed at a C=C bond.
<h3>What is IR spectra?</h3>

The percent transmittance (or absorbance) of the radiation through the molecule against the radiation's wave number forms the IR spectrum.

Learn more about IR spectra here:

brainly.com/question/22033021

#SPJ4

3 0
2 years ago
Read 2 more answers
If we mix 25 grans if sodium oxide with a large amount of potassium chloride, how many grams of sodium chloride should be produc
amid [387]

Answer:

47.2 g

Explanation:

Data given:

mass of Sodium oxide (Na₂O) = 25 grams

mass of potassium chloride (KCl) = excess

amount of sodium chloride (NaCl) = ?

Solution:

First we look for reaction of sodium oxide with potassium chloride.

                    Na₂O + 2 KCl -----------> 2 NaCl + K₂O

As we know that potassium chloride is in excess amount and sodium oxide is 25 g so it means sodium oxide is a limiting reactant and amount of sodium chloride depends on the amount of sodium oxide.

So, now we will look for mole mole ration of Na₂O to NaCl.

                    Na₂O + 2 KCl -----------> 2 NaCl + K₂O

                    1 mol                              2 mol

from above equation we come to know that 1 mole of Na₂O gives 2 moles of NaCl.

Now convert moles to mass

As we Know

Molar mass of Na₂O = 2(23) + 16 = 62 g/mol

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

So

                  Na₂O              +   2 KCl    ----------->      2 NaCl          +      K₂O

             1 mol (62 g/mol)                                   2 mol (58.5 g/mol)

                  62 g                                                          117 g

So, it means that 62 g of Na₂O produce 117 g of NaCl then how many grams of NaCl will be produce by 25 g of Na₂O

Apply unity formula

                           62 g of Na₂O ≅ 117 g of NaCl

                           25 g of Na₂O ≅ X g of NaCl

Do cross multiplication

                          X g of NaCl = 117 g x 25 g / 62 g

                          X g of NaCl = 47.2 g

So,

25 g of Na₂O gives 47.2 grams of NaCl.

4 0
3 years ago
What is simple displacement reaction???give examples.
VARVARA [1.3K]

Answer:

<h2>Hey rose why you deleted my comments</h2>

3 0
3 years ago
Part B Redox titrations are used to determine the amounts of oxidizing and reducing agents in solution. For example, a solution
MissTica

Answer:

0,508g of H₂O₂

Explanation:

For the reaction:

2KMnO₄(aq) + H₂O₂(aq) + 3H₂SO₄(aq) → 3O₂(g) + 2MnSO₄(aq) + K₂SO₄(aq) + 4H₂O(l)

2 moles of KMnO₄ react with 1 mol of H₂O₂.

In the titration, moles of KMnO₄ required were:

1,68M×0,0178L = 0,0299 moles of KMnO₄. Moles of H₂O₂ are:

0,0299 moles of KMnO₄×\frac{1molH_{2}O_{2}}{2molKMnO_{4}} = 0,01495 moles of H₂O₂. As molar mass of H₂O₂ is 34,01g/mol, mass of H₂O₂ was dissolved is:

0,01495 moles of H₂O₂×\frac{34,01g}{1molH_{2}O_{2}} = <em>0,508g of H₂O₂</em>

5 0
2 years ago
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